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il63 [147K]
3 years ago
8

How can you solve an equation or inequality in one variable?

Mathematics
1 answer:
zimovet [89]3 years ago
4 0

In order to solve an equation for a variable, we need to isolate that variable on one side of the equation (either left side or right side).

Following are some steps to solve equation/inequality in one variable:

1) Get rid constant number from on side by applying reverse operation of addition or subtraction.

2) Get rid variable terms from other side by applying reverse operation of addition or subtraction.

3) Combine like terms on both sides.

4) Get rid any coefficent ( a number in front of a variable) by dividing from both sides.

5) Finally you get a variable on one side and solution on other side.

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Is this rational or irrational I really need help ASAP! Will mark brainlist.
ryzh [129]

Answer:

Rational

Step-by-step explanation:

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3 years ago
What is the solution of the following question?<br> x^2+10x+25=12
zalisa [80]
Make equal to 0
minus 12from both sides
x^2+10x+13=0
we can't factor so use quadratic formula

x= \frac{-b+/- \sqrt{b^{2}-4ac} }{2a}
x= \frac{-10+/- \sqrt{10^{2}-4(1)(13)} }{2(1)}
x= \frac{-10+/- \sqrt{100-52} }{2}
x= \frac{-10+/- \sqrt{48} }{2}
x= \frac{-10+/- 4\sqrt{3} }{2}
x= -5+/- 2\sqrt{3}


x= -5+ 2\sqrt{3} or -5- 2\sqrt{3}

aprox
x=-1.5359 or -8.4641





3 0
3 years ago
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Please tell me what question b and c is ASAP
artcher [175]

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7 0
2 years ago
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Geometry homework I really don’t understand this so can someone please help me.
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3 years ago
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What is the Volume of the square pyramid? (Round to the nearest tenth as needed)
goldenfox [79]

Answer:

5229 mm³

Step-by-step explanation:

Volume of square pyramid

\sf \boxed{Volume \ of \ the \ square \ pyramid = \dfrac{1}{3}*b^2*H}

      b = base length = 25 mm

       H = height

         We have to find 'H' using Pythagorean theorem,

              slant height (hypotenuse) = 28 mm

                                                  leg₁ = base length  ÷ 2 = 25÷2 = 12.5

                                                  leg₂ = H

     H² + (12.5)² = 28²

                  H²   = 784 - 156.25

                         = 627.75

                   \sf H = \sqrt{627.75}

                 H = 25.01 mm

          \sf  \text{Volume of square pyramid =$\dfrac{1}{3}*25*25*25.1$ }

                                                     = 5229 mm³

                                                     

       

\sf \boxed{\text{Volume of square pyramid = \dfrac{1}{3}*25*25*28}}

3 0
2 years ago
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