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umka2103 [35]
3 years ago
14

How many times can 7 go 48 with out going over?

Mathematics
1 answer:
Paul [167]3 years ago
8 0
48÷7= 6.85
That would be your answer
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Find (f/g) (x) for the functions provided: ƒ(x) = x3 − 27, g(x) = 3x − 9
AnnZ [28]

Answer:

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

Step-by-step explanation:

We have been given that

f(x)=x^3-27,g(x)=3x-9

We can use the formula for difference of cubes to simplify the function f(x)

difference of cubes -  a^3-b^3=(a-b)(a^2+ab+b^2)

f(x)=x^3-27\\\\=x^3-3^3\\\\=(x-3)(x^2+3x+9)

And g(x) can be written as

g(x)=3x-9\\=3(x-3)

Thus, we have

(\frac{f}{g})(x)=\frac{(x-3)(x^2+3x+9)}{3(x-3}

On cancelling the common factors, we get

(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)

5 0
3 years ago
Find the missing lengths of the sides.
ra1l [238]
The answer is C, you can solve this by sin(30)= 8/c since sine is opposite over hypotenuse and since c equals 16 there is only one possible solution 
4 0
4 years ago
1. How many planes are shown in the figure?
g100num [7]

Answer:8 planes are shown in the figure

Step-by-step explanation:

5 0
3 years ago
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Solve the rational function of (check image) and check for extraneous solutions
Oxana [17]

Answer:

Option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

Step-by-step explanation:

Given the expression

\frac{5}{x}=\frac{4x+1}{x^2}

Solving the rational function

\frac{5}{x}=\frac{4x+1}{x^2}

Apply fraction across multiply: if \frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5x^2=x\left(4x+1\right)

Subtract x(4x+1) from both sides

5x^2-x\left(4x+1\right)=x\left(4x+1\right)-x\left(4x+1\right)

Simplify

5x^2-x\left(4x+1\right)=0

5x² - 4x² - x = 0

x² - x = 0

Factor x² - x = x(x-1)

so

x(x-1) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x=0\quad \mathrm{or}\quad \:x-1=0

Thus, the solution to the equation is:

x=0,\:x=1

But, it is clear that if we substitute x = 0, the equation becomes undefined because we can not have the denominator to be 0.

In other words, the equation is undefined for x = 0

Thus, x = 0 is an extraneous solutions.

Therefore, option A is correct.

i.e. x = 1, x = 0 is an extraneous solution.

5 0
3 years ago
Write this number in word form 310763136
Tresset [83]
Three hundred and ten million seven hundred and sixty three one hundred and thirty six
3 0
4 years ago
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