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3 years ago

How many times can 7 go 48 with out going over?

Mathematics

1 answer:

Paul [167]3 years ago

8 0

48÷7= 6.85
That would be your answer

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3 |14-m| > 18<br> PLEASE HELPP

igor_vitrenko [27]

we conclude that the inequality can be written as the compound inequality:

m < 8

m > 20

<h3></h3><h3>How to solve the inequality for m?</h3>

Here we have the inequality:

3*|14 - m| > 18

We want to isolate m, so we start by dividing both sides by 3:

|14 - m| > 18/3 = 6

Now we can decompose the inequality in two:

14 - m > 6

14 - m < - 6

Solving both for m, we get:

14 - 6 > m

14 + 6 < m

8 > m

20 < m

Then we conclude that the inequality can be written as the compound inequality:

8 > m

20 < m

If you want to learn more about inequalities:

brainly.com/question/25275758

#SPJ1

5 0

2 years ago

RUDIKE [14]

Answer:

least possible number of sweets = lowest common multiple of 5,6 & 10 - 2

-I hope this helps! I got it figured out until near like the very end.-

-Please mark as brainliest!- Thanks!

5 0

3 years ago

Plssss plsss helppppp

ElenaW [278]

Put the numbers in order
4 5 7 9 11 12 12 14

Find median 9+11=20/2 so 10

Now find median for the first 1/2 of numbers and the second half
6 12

Find difference 12-6=6
IQR=6

7 0

3 years ago

Read 2 more answers

What is (2x3) squared + 5 squared?

boyakko [2]

6 squared is 36 and 5 squared is 25 so if you add them together you get 61.

3 0

4 years ago

Read 2 more answers

Use the formula to evaluate the series -3+6-12+24-...-a7

vichka [17]

<span>-3+6-12+24 <---- notice the terms firstly, they go as

-3 , +6 , -12 , +24 ,.... <---- to get the next term's value, you multiply it by -2

thus, is a geometric sequence, and -2 is the "common difference", and the first term is -3 of course.

so... what's the sum of the first 7 terms?

</span> $\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=-3\\
r=-2\\
n=7
\end{cases}$
<span>
</span> $\bf S_7=\sum\limits_{i=1}^{7}\ -3\cdot (-2)^{i-1}\implies 
S_7=-3\left( \cfrac{1-(-2)^7}{1-(-2)} \right)
\\\\\\
S_7=-3\left( \cfrac{1-(-128)}{1+2}\right)\implies S_7=-3\left( \cfrac{129}{3} \right)\implies S_7=-3(43)
\\\\\\
S_7=-129$ <span>
</span>

8 0

4 years ago