Answer:
<em>The percentage of males are not at least 172 pounds</em>
P(X⁻ ≥ 172) = 0.26
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that 74% of 19 -year -old males are at least 172 pounds
Let 'X' be a random variable in a binomial distribution
P( X≥172) = 74% = 0.74
<em>we have to find that the percentage of males are not at least 172 pounds</em>
<u><em>Step(ii):-</em></u>
<em>The probability of males are not at least 172 pounds</em>
P(X⁻≥172) = 1- P( X≥172)
= 1- 0.74
<em> = 0.26</em>
<u><em>Final answer:-</em></u>
<em>The percentage of males are not at least 172 pounds</em>
P(X⁻ ≥ 172) = 0.26
<u><em></em></u>
The coordinates are (-4,0),(0,-1)
Answer:
D
Step-by-step explanation:
Given
4x + 8.2 ≤ 32.2 ( subtract 8.2 from both sides )
4x ≤ 24 ( divide both sides by 4 )
x ≤ 6 → D
50 =2×5×5
125=5×5×5
Hoghest common factor = 5×5
=25
Answer:
49038.0952
Step-by-step explanation:
x+0.05x=51490
1.05x/1.05= 51490/1.05
x=49038.0952
