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3 years ago

15

The residents of a village want to paint a sign that shows the elevation of their village to the sea. Their altimeter shows +2,1

00 feet. What should their signboard read?

1 answer:

kirill [66]3 years ago

7 0

Answer:

Wassss uppppp

Step-by-step explanation:

i dont know

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What is<br> 3a+6b= 4 for b<br> Really need help

saw5 [17]

3a+6b=4

-3a both sides

6b=4-3a

÷6 both sides

b=2/3 -1/2 a

5 0

3 years ago

Choose the correct x-intercepts for the following quadratic fiction

Butoxors [25]

Answer:

Could you please add a photo or the quadratic function?

6 0

3 years ago

What is 35% of 240?

astraxan [27]

Answer:

Step-by-step explanation:

You need to multiply .35 * 240 which = 84.

of means multiply.

4 0

3 years ago

Read 2 more answers

35 POINTS AVAILABLE

aliina [53]

Answer:

Part 1) The length of each side of square AQUA is $3.54\ cm$

Part 2) The area of the shaded region is $(486\pi-648)\ units^{2}$

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

$A=\pi r^{2}$

we have

$A=25\pi\ cm^{2}$

substitute in the formula and solve for r

$25\pi=\pi r^{2}$

simplify

$25=r^{2}$

$r=5\ cm$

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

$SU=r=5\ cm$

Let

x------> the length side of the square

Applying the Pythagoras Theorem

$5^{2}=x^{2} +x^{2}$

$5^{2}=2x^{2}$

$x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm$

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=AB=18\ units$

substitute in the formula

$A=\pi (18)^{2}=324\pi\ units^{2}$

step 2

Find the length of each side of square BCDE

we have that

$AB=18\ units$

The diagonal DB is equal to

$DB=(2)18=36\ units$

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

$36^{2}=x^{2} +x^{2}$

$1,296=2x^{2}$

$648=x^{2}$

$x=\sqrt{648}\ units$

step 3

Find the area of the square BCDE

The area of the square is

$A=(\sqrt{648})^{2}=648\ units^{2}$

step 4

Find the area of the smaller circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=(\sqrt{648})/2\ units$

substitute in the formula

$A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}$

step 5

Find the area of the shaded region

$324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}$

7 0

3 years ago

two-point charges are 10.0 cm apart and have charges of 2.0 uc and -2.0uc respectively What is the magnitude of the electrical f

maks197457 [2]

Answer:

The electric field generated by a point charge is given by:

where

is the Coulomb's constant

Q is the charge

r is the distance from the charge

We want to know the net electric field at the midpoint between the two charges, so at a distance of r=5.0 cm=0.05 m from each of them.

Let's calculate first the electric field generated by the positive charge at that point:

where the positive sign means its direction is away from the charge.

while the electric field generated by the negative charge is:

where the negative sign means its direction is toward the charge.

If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:

Read more on Brainly.com - brainly.com/question/9699355#readmore

Step-by-step explanation:

6 0

3 years ago