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Pachacha [2.7K]
3 years ago
5

7. Jake wants to estimate 15.92 +0.85.

Mathematics
2 answers:
Marianna [84]3 years ago
8 0

He can round 0.85 up, because its over .50.

He can round 15.92 up, because it is also over .50.

16 + 1 = 17 is the estimate.

Allushta [10]3 years ago
8 0

Answer:17

Step-by-step explanation:

he can either round up .85 to 1 and 15.92 to 16 and add from there or round up the answer when you don’t estimate

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B- 8 ounces of blue paint mixed with 6 ounces of red paint

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What’s 5 equivalent ratios to 27:9
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Read 2 more answers
Can I have some help?
earnstyle [38]
#1) so if the ratio is 2/3 and the other fraction is 16/?, all you have to do is figure out what it took to get there. For example, if the beginning fraction is 2/3 and the second one is 16/?, we at least know that 2 times 8 is 16, so all we have to do is multiply 3 times 8 to get the bottom number which is 24. So 24 is the amount of tan tiles they will need.

(I’ll comment the next two answers)
3 0
3 years ago
The quotient of two numbers is 3 their product is 3 what are the two numbers
ruslelena [56]

Answer:

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3 0
3 years ago
If 2tanA=3tanB then prove that,<br>tan(A+B)= 5sin2B/5cos2B-1​
Fed [463]

By definition of tangent,

tan(A + B) = sin(A + B) / cos(A + B)

Using the angle sum identities for sine and cosine,

sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

yields

tan(A + B) = (sin(A) cos(B) + cos(A) sin(B)) / (cos(A) cos(B) - sin(A) sin(B))

Multiplying the right side by 1/(cos(A) cos(B)) uniformly gives

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) tan(B))

Since 2 tan(A) = 3 tan(B), it follows that

tan(A + B) = (3/2 tan(B) + tan(B)) / (1 - 3/2 tan²(B))

… = 5 tan(B) / (2 - 3 tan²(B))

Putting everything back in terms of sin and cos gives

tan(A + B) = (5 sin(B)/cos(B)) / (2 - 3 sin²(B)/cos²(B))

Multiplying uniformly by cos²(B) gives

tan(A + B) = 5 sin(B) cos(B) / (2 cos²(B) - 3 sin²(B))

Recall the double angle identities for sin and cos:

sin(2x) = 2 sin(x) cos(x)

cos(2x) = cos²(x) - sin²(x)

and multiplying uniformly by 2, we find that

tan(A + B) = 10 sin(B) cos(B) / (4 cos²(B) - 6 sin²(B))

… = 10 sin(B) cos(B) / (4 (cos²(B) - sin²(B)) - 2 sin²(B))

… = 5 sin(2B) / (4 cos(2B) - 2 sin²(B))

The Pythagorean identity,

cos²(x) + sin²(x) = 1

lets us rewrite the double angle identity for cos as

cos(2x) = 1 - 2 sin²(x)

so it follows that

tan(A + B) = 5 sin(2B) / (4 cos(2B) + 1 - 2 sin²(B) - 1)

… = 5 sin(2B) / (4 cos(2B) + cos(2B) - 1)

… = 5 sin(2B) / (4 cos(2B) - 1)

as required.

5 0
2 years ago
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