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Ainat [17]
3 years ago
14

What is the product?

Mathematics
2 answers:
Taya2010 [7]3 years ago
6 0

Answer:

4.84096e+25

<h2><u>Hope This Helped!</u></h2>

Marina CMI [18]3 years ago
6 0

Answer:

<h2>3.) 4.84096 x 10^25</h2>

Step-by-step explanation:

<h2>Hope it helps u!!!! </h2>
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Select the expressions that are equivalent to 10 + 2x + 5y + 3x.
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Ostrovityanka [42]
I think it’s C. Sorry if I’m incorrect
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A college job placement office collected data about students’ GPAs and the salaries they earned in their first jobs after gradua
frez [133]

Answer:

X is the GPA

Y is the Salary

Standard deviation of X is 0.4

Standard deviation of Y is 8500

E(X)=2.9

E(Y)=47200

We are given that The correlation between the two variables was r = 0.72

a)y = a+bx

b = \frac{\sum(x_i-\bar{x})(y_i-\bar{y})}{\sum(x_i-\bar{x})^2} = \frac{r \times \sqrt{var(X) \times Var(Y)}}{Var(X)} =  \frac{0.72 \times \sqrt{0.4^2 \times 8500^2}}{0.4^2} = 15300

a=y-bx = 47200-(15300 \times 29) = 2830

So, slope =  15300

Intercept =  2830

So, equation : y = 2830+15300x

b) Your brother just graduated from that college with a GPA of 3.30. He tells you that based on this model the residual for his pay is -$1880. What salary is he earning?

y = 2830+15300 \times 3.3 = 53320

Observed salary = Residual + predicted = -1860+53320 = 51440

c)) What proportion of the variation in salaries is explained by variation in GPA?

The proportion of the variation in salaries is explained by variation in GPA = r^2 = (0.72)^2 =0.5184

8 0
3 years ago
What is the percent discount if a 12,500 car is now on special for 10,250?
LenaWriter [7]

Answer:

Step-by-step explanation:

the answer is 2250 percent is = 22.5

4 0
3 years ago
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An automobile manufacturer has given its van a 47.2 miles/gallon (MPG) rating. An independent testing firm has been contracted t
7nadin3 [17]

Answer:

A

The  test statistics is  t  = -1.7

B

The  Null and  Alternative hypothesis are

      H_o  :  \mu = 47.2   and  H_a :  \mu \ne  47.2

Step-by-step explanation:

From the question we are told that

    The population mean is  \mu  =  47.2 miles/gallon(MPG)

    The sample size is  n =  250 \ van

     The  sample mean is  \= x  =  47.0

      The sample  standard deviation is  \sigma  =  1.9

      The level of significance is  \alpha  =  0.02

Given that the value which the manufacturer gave the automobile is  47.2 and  it is believed that this is not correct, then  

The  Null Hypothesis is  

        H_o  :  \mu = 47.2

The alternative Hypothesis  is  

        H_a :  \mu \ne  47.2

The test statistics can be mathematically evaluated as  

        t  =  \frac{\= x- \mu}{\frac{\sigma }{\sqrt{n} } }

substituting values

        t  =  \frac{\= 47- 47.2}{\frac{1.9 }{\sqrt{250} } }

       t  = -1.7

7 0
3 years ago
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