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3 years ago

Five less than three. Times the length L

Mathematics

2 answers:

Marina86 [1]3 years ago

7 0

the answer is...

3L-5

anyanavicka [17]3 years ago

4 0

This cannot be expressed as an answer but the expression for that is 3L-5

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Solve the following question. *

n200080 [17]

Answer:

The mean of x and y is equal to t.

Step-by-step explanation:

Given that,

The mean of t and t+2 is x.

The mean of t and t-2 is y.

i.e.

$x=\dfrac{t+t+2}{2}\\\\x=(t+1)$

and

$y=\dfrac{t+t-2}{2}\\\\x=(t-1)$

The mean of x and y is :

$M=\dfrac{x+y}{2}\\\\M=\dfrac{(t+1)+(t-1)}{2}\\\\M=\dfrac{2t}{2}\\\\M=t$

Hence, the mean of x and y is equal to t.

7 0

3 years ago

4. Represent the ordered pairs in the mapping diagram as a set of ordered pairs and as a table.

Firlakuza [10]

Answer/Step-by-step explanation:

✔️As a set of order pairs, the mapping can be represented as (x, y), where x = input and y = output.

Thus:

{(1, 6), (2, 6), (3, 6), (4, 8)}

✔️As a table we have input as x, and y as output, such as:

x | y

1 | 6

2 | 6

3 | 6

4 | 8

3 0

3 years ago

matrenka [14]

Answer:

Step-by-step explanation:

D.works many year for a nation

8 0

2 years ago

Show work please!...

Leni [432]

Answer:what goes around comes around

Step-by-step explanation:

"i need points too thanks"

7 0

2 years ago

Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2

boyakko [2]

<u>Given</u>:

The quadratic equation is $x^{2}=-5 x-3$

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

$x^{2}+5 x+3=0$

The solution of the equation can be determined using quadratic formula.

Thus, we get;

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}$

$x=\frac{-5 \pm \sqrt{25-12}}{2 }$

$x=\frac{-5 \pm \sqrt{13}}{2 }$

Thus, the two roots of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

Hence, the solutions of the equation are $x=\frac{-5 + \sqrt{13}}{2 }$ and $x=\frac{-5- \sqrt{13}}{2 }$

6 0

3 years ago

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