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kakasveta [241]
3 years ago
10

Below is the number of games each quarterback in the Northwest division has played this season.

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0
You may want to include a question
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What is equivelant to 5 to the power of -1?
Mazyrski [523]
\frac{1}{5} Or  0.2
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3 years ago
How can you recognize and interpret associations in two-way tables?
galina1969 [7]

Answer:

Sometimes the best way to tell whether two variables are associated is to ask yourself whether they are not associated. Think backward. In a two-way frequency table, if the relative frequencies for one variable are the same (or close) for all categories of another variable, there is no (or little) associa

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Write the equation of the line that passes through the points (-3,-7) and (-1,3)
Lina20 [59]

Answer:

This is the answer of your question.

4 0
3 years ago
Suppose your new business made a profit during the first year of $3000. If the profit increased 12% per year, find the total of
mariarad [96]

Answer:

Therefore the total of all profit earned by the end of of the the first 5 years is $19,058.542.

Step-by-step explanation:

To find total profit earned per year, we need to use the compound growth formula.

The compound growth formula:

A= P(1+r)^t

A= Amount after t years

P= initial amount

r= rate of growth

t= time in year.

Given that,

New business made a profit during the first year of $3000.

If the profit increased 12% per year.

Here P= $3,000 and r =12%=0.12 , t=1 years

Plugging all value in the above  formula:

A=3000(1+0.12)^1

   =3000(1.12)

  =$3360

Profit after 2 year is $3,360.

Now, P= $3,000 and r =12%=0.12 , t=3 years

A=3000(1+0.12)^2

   =3000(1.12)²

   =$3763.2

Similar the profit at 4 year is

A=3000(1+0.12)^3

   =3000(1.12)³

   =$4214.784

The profit at 5th year is

A=3000(1+0.12)^4

   =3000(1.12)⁴

   =$4720.558

Therefore the total of all profit earned by the end of of the the first 5 years is=$(3,000+3360+3763.2+4214.784+4720.558)

          =$19,058.542

6 0
3 years ago
A high school held an election for class president. Exactly 1,000 votes were cast and they were all for either Gillian or Clive.
lisov135 [29]

Answer: 60%

1000÷2=500

Clive: 500-100= 400

Gillian: 500+100= 600 (Because Gillian has 100 more votes than Clive)

\frac{600}{1000} \times 100\%  = 60\%

8 0
3 years ago
Read 2 more answers
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