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dimulka [17.4K]

2 years ago

11

Find 1/8 of 12. Express your answer in simplest form. 1 1/2 2/3 1/96 12/8

2 answers:

olga nikolaevna [1]2 years ago

6 0

Answer:

1 1/2

Step-by-step explanation:

igor_vitrenko [27]2 years ago

4 0

Question

Find 1/8 of 12. Express your answer in simplest form.

1 1/2

2/3

1/96

12/8

Answer:

<h2>1 1/2</h2>

Step-by-step explanation:

12 : 8 = 1.5 (1 1/2)

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A school newspaper decides to survey all the students enrolled in a gym class to determine the percentage of these students who

pishuonlain [190]

Answer:

A sudents who take gym class

Step-by-step explanation:

the survey only asks for all the students enrolled in a gym class so they can compare with the data for all the students enrolled in the football team

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3 years ago

Jason designs a rectangular sandbox. He models the perimeter of the sandbox using the expression 8l+2, where l is the length of

inn [45]

Answer:

A .The expression 2l+2(3l+1) shows the width is 1 more than 3 times the length.

Step-by-step explanation:

p = 8l + 2

Length = l

Width:

2w = p - 2l

2w = (8l + 2) - 2l

2w = 6l + 2

w = 3l + 1

Therefor w is 3 times the length plus 1

7 0

3 years ago

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago

How can you find the sum of the angle measures in a triangle?

sattari [20]

Answer:

a Euclidean space, the sum of angles of a triangle equals the straight angle (180 degrees, π radians, two right angles, or a half-turn). A triangle has three angles, one at each vertex, bounded by a pair of adjacent sides.

8 0

2 years ago

What’s the correct answer

ludmilkaskok [199]

I think it’s C i think is right

7 0

2 years ago