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4 years ago

What is the product of 127 and 32

Mathematics

1 answer:

Sedaia [141]4 years ago

4 0

4,064 because product is when you multiply so 127 * 32

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Learning Task Find the perimeter and area of each figure Perimeter Area om som So

nexus9112 [7]

Answer:

Step-by-step explanation:

1. Perimeter: 8cm + 8cm + 3cm + 3cm = 22cm

Area: 8cm x 3cm = 24cm

2. Perimeter: 5m + 5m + 5m + 5m = 20m

Area: 5m x 5m = 25m

3. Perimeter: 4m + 4m + 18m + 18m = 44m

Area: 4m x 18m = 72m

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3 years ago

ANSWER QUICK.

Debora [2.8K]

Answer:

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Step-by-step explanation:

39.00 x .14 = 5.46

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6 0

3 years ago

Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set: A

gtnhenbr [62]

Answer:

$A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$

Step-by-step explanation:

Given: $\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}$ , $\text{A}=\left \{\text{q, s, u, w, y} \right \}$ , $\text{B}=\left \{\text{q, s, y, z} \right \}$ ,

$\text{C}=\left \{\text{v, w, x, y, z} \right \}$ .

To find: The elements in the set $A \cup C$ .

Solution:

We have,

$\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}$

$\text{A}=\left \{\text{q, s, u, w, y} \right \}$

$\text{B}=\left \{\text{q, s, y, z} \right \}$

$\text{C}=\left \{\text{v, w, x, y, z} \right \}$

Now, $A \cup C$ will contain all the elements in the set $A$ and all the elements in set $C$ .

So, $A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$ .

Hence, $A \cup C=\left \{ \text{q, s, u, v, w, x, y, z} \right \}$ .

7 0

3 years ago

Will give brainliest

elena55 [62]

Answer:3

I’m sorry if it’s wrong

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Suppose that y is directly proportional to x, and y = 150 when x = 15. What is the constant of proportionality?

galina1969 [7]

Answer: The required constant of proportionality is 10.

Step-by-step explanation: Given that y is directly proportional to x, and y = 150 when x = 15.

We are to find the constant of proportionality.

According to the given information, we can write

$y\propto x\\\\\Rightarrow y=kx~~~~~~~~~~~~~~~~[\textup{where k is the constsnt of propotionality}].$

When y = 150 and x = 15, we get from the above equation that

$y=kx\\\\\Rightarrow 150=k\times15\\\\\Rightarrow k=\dfrac{150}{15}\\\\\Rightarrow k=10.$

Thus, the required constant of proportionality is 10.

3 0

3 years ago