Jasmine created this spinner to predict whether a randomly selected student in her school will be traveling during the upcoming
2 answers:
Answer:
The number of students Jasmine surveyed indicated they would be traveling during the holiday break is 9.
Step-by-step explanation:
The spinner created by Jasmine, to predict whether a randomly selected student in her school will be traveling during the upcoming holiday break, has 8 equal sections labeled:
{yes, yes, no, no, no, no, no, no}
So, there are two sections labeled yes and six labelled as no.
Compute the probability of a yes as follows:
Jasmine selected <em>n</em> = 36 students in her gym class.
If a student in her school will be traveling during the upcoming holiday break is independent of the other students.
Let the random variable <em>X</em> be defined as the number f students that will be traveling during the upcoming holiday break.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 36 and <em>p</em> = 0.25.
Compute the expected value of <em>X</em> as follows:
Thus, the number of students Jasmine surveyed indicated they would be traveling during the holiday break is 9.
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Answer:
y(s) =
we will compare the denominator to the form
comparing coefficients of terms in s
1
s: -2a = -10
a = -2/-10
a = 1/5
constant:
hence the first answers are:
a = 1/5 = 0.2
β = 5.09
Given that y(s) =
we insert the values of a and β
=
to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A
5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)
-52 = B(26)
B = -52/26 = -2
to get A lets substitute s=0.4
5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)
-51 = 0.2A - 52.08
0.2A = -51 + 52.08
A = -1.08/0.2 = 5.4
<em>the constants are</em>
<em>a = 0.2</em>
<em>β = 5.09</em>
<em>A = 5.4</em>
<em>B = -2</em>
<em></em>
Step-by-step explanation:
- since the denominator has a complex root we compare with the standard form
- Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
- substitute the values gotten into the function
- Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
- after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above
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