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3 years ago

What fraction is not equivalent to 36/60

Mathematics

2 answers:

AveGali [126]3 years ago

7 0

Any fraction but the equivalent of 36/60 36/60= 3/5 reduced

Andreyy893 years ago

3 0

Fractions that aren't equivalent would be 30/60, 34/60 and anything that cannot be the same as 36/60.

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The perimeter of the rectangle below is 174 units. Find the length of side BC. Write your answer without variables.

hodyreva [135]

BC= 39

Explanation:

4z+4z+3z+3+3z+3=174

8z+6z+6=174

14z+6=174

Subtract 6 from both sides

14z=168

Z=12

So then 3*12+3=39

And you can check by doing 39+39+48+48
And it equals 174

4 0

3 years ago

Determine whether or not F is a conservative vector field. If it is, find a function f such that F = ∇f. (If the vector field is

Elis [28]

In order for F to be conservative, there must be a scalar function f such that the gradient of f is equal to F. This means

$\dfrac{\partial f}{\partial x}=3x^2-2y^2$

$\dfrac{\partial f}{\partial y}=4xy+4$

Integrate both sides of the first equation with respect to x :

$f(x,y)=x^3-2xy^2+g(y)$

Differentiate both sides with respect to y :

$\dfrac{\partial f}{\partial y}=-4xy+\dfrac{\mathrm dg}{\mathrm dy}=4xy+4\implies\dfrac{\mathrm dg}{\mathrm dy}=8xy+4$

But we assume g is a function of y, which means its derivative can't possibly contain x, so there is no scalar function f whose gradient is F. Therefore F is not conservative.

8 0

3 years ago

Converse of Pythagorean theorem, Find the missing side length of each triangle round to the nearest 10th if necessary.

torisob [31]

The formula for the Pythagorean theorem is,

$\text{Hypotenuse}^2=Opposite^2+Adjacent^2$

8 0

1 year ago

What times 8 equals 3

Nadusha1986 [10]

Answer:

2.6

Step-by-step explanation:

i hope this helps bro because i know this is the right answer because i think so and im pretty sure im right because I think so

5 0

3 years ago

Read 2 more answers

If a quadratic equation with real coefficients has a discriminant of 3 then the two roots must be

lukranit [14]

In a quadratic equation

q(x) = ax^2 + bx + c

The discriminant is = b^2 - 4ac

We have that discriminant = 3

If b^2 - 4ac > 0, then the roots are real.

If b^2 - 4ac < 0 then the roots are imaginary

In this problem b^2 - 4ac > 0 3 > 0

then the two roots must be real

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3 years ago