Answer:
1. 516 ppm; 2. 561 ppm
Step-by-step explanation:
1. CO₂ increase at old rate
Time = 2100 - 2010 = 90 years
Increase in CO₂ = 90 yr × (1.4 ppm/1 yr) = 126 ppm
CO₂ in 2010 = 390 + 126 = 516 ppm
At the old rate, the CO₂ concentration in 2100 will be 516 ppm.
2. CO₂ increase at new rate
Time = 2100 - 2010 = 90 years
Increase in CO₂ = 90 yr × (1.9 ppm/1 yr) = 171 ppm
CO₂ in 2010 = 390 + 171 = 561 ppm
At the new rate, the CO₂ concentration in 2100 will be 561 ppm.
4x + 5y = 2(x + 3y)
4x + 5y = 2x + 6y <em>distributed 2 on the right side</em>
2x + 5y = 6y <em>subtracted 2x from both sides</em>
2x = y <em>subtracted 5y from both sides</em>
if y = 2x
then 17(y) = 17(2x)
17y = 34x
Answer: 34x
Derivating the equation:
So the slope of the tangent in the point (0,1) is:
Then, the slope of the normal (n) line in the point (0,1) is:
Answer:
f(x) = 86(1.04)x; grows approximately at a rate of 0.4% daily
Step-by-step explanation:
The base of the exponential function is 1.29 for 7 days, as in
f(x) = 86*(1.29)^x
The new rate for days can be calculated by dividing x by 7 (where x remains the number of weeks), namely
f(x) = 86*1.29^(x/7)
Using the law of exponents, b^(x/a) = b^(x*(1/a)) = (b^(1/a))^x
we simplify by putting b=1.29, a=7 to get
f(x) = 86*(1.29^(1/7))^x
f(x) = 86*(1.037)^x since 1.29^(1/7) evaluates to 1.037
Rounding 1.037 to 1.04 we get a (VERY) approximate function
Gallons of water drank in 4 days = 120
Gallons of water drank in a day = 120/4
= 30
Gallons of water drank in 28 days = 30 × 28
= 840
