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Leviafan [203]
3 years ago
11

Which question can be answered by finding 1 1/4 divided by 1/2

Mathematics
2 answers:
densk [106]3 years ago
8 0

Answer:

The second one is correct.

Step-by-step explanation:

Do you need an explanation?

Just  tell me if you do...

kotykmax [81]3 years ago
8 0

Answer:

The second one

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Dilate the segment about the origin by a scale factor of 1 /2 What are the coordinates of B'? please help
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Answer:

(1,-2) edge2020

Step-by-step explanation:

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What is the definition of exponential decay?
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When a population or group of something is declining, and the amount that decreases is proportional to the size of the population.
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3 years ago
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Find the slope of the line that passes through each pair of points.
e-lub [12.9K]

Answer:

<u>0.5</u>

Step-by-step explanation:

Slope (m) =  

ΔY

ΔX

=  

1

2

= 0.5

θ =  

arctan( ΔY ) + 180°

ΔX

= 206.56505117708°

ΔX = 0 – 2 = -2

ΔY = 0 – 1 = -1

Distance (d) = √ΔX2 + ΔY2 = √5 = 2.2360679774998

Equation of the line:

y = 0.5x

When x=0, y = 0

When y=0, x = -0

BRAINIEST PLEASE??

8 0
2 years ago
F(x)=x+2/2 what is the value of f(-8)<br><br> A.-4<br> B.-3<br> C.-5<br> D.-6
bonufazy [111]
Answer: Choice B) -3

------------------------------------------------------

Work Shown:

f(x) = (x+2)/2
f(-8) = (-8+2)/2 ... replace every x with -8; use PEMDAS
f(-8) = (-6)/2
f(-8) = -3

4 0
3 years ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
2 years ago
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