Answer:
let first equation be y=x^2-14x+23
second equation be y=-3x+5
now substitute the vale of y in equation second
y=-3x+5
x^2-14x+23=-3x+5
x^2-14x+3x=5-23
x^2-11x=-18
x^2-11x+18=0
x^2-(9+2)x+18=0
x^2-9x-2x+18=0
x(x-9)-2(x-9)=0
(x-2)(x-9)=0
either x-2=0 Or, x-9=0
x-2=0
x=0+2
x=2
x-9=0
x=0+9
x=9
therefore x=2,9
Step-by-step explanation:
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Answer:
Step-by-step explanation:
The volume of a cylinder is given by :
.....(1)
Where
r and h are the radius and the height of the cylinder.
We need to solve the equation of r. Cross multiplying both sides in equation (1).
Dividing both sides by 
. So,
So, the radius of the cylinder is equal to 
.
f - green (A)
f' - red (B)
f'' - blue (C)
The graph of f attains local extrema at the same points that f' = 0. There's evidence of this at x = 0 and between x = 3 and x = 3.5. (At both points, curve A attains a maximum, while curve B crosses the x-axis.)
Similarly, the graph of f' attains local extrema at the same points that f'' = 0. This is seen between x = 1.5 and x = 2. (B has a max, C crosses axis)
Also, the graph of A is continuous at x = 1.5 but exhibits a sharp turn, so at this point f is not differentiable and the graph of f' (and subsequently f'') is not continuous.
528/3=176
go one lower and one higher
175+176+177 = 528
Answer:
x = 2
Step-by-step explanation:
The mean is
3 + 7 + 8 + 10 + x
------------------------- = 6
5
Multiplying both sides by 5, we get:
3 + 7 + 8 + 10 + x = 30
Then 28 + x = 30, so that x must be 2
x = 2
