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maw [93]
3 years ago
15

Explain why it is possible to draw more than two different rectangles with an area of 100 square units, but it is not possible t

o draw more than two different rectangles with an area of 55 square units. The sides of the rectangles are whole numbers.
Mathematics
1 answer:
earnstyle [38]3 years ago
7 0

Answer:

100 has more divisors than 55.

Step-by-step explanation:

The prime factorization of 100 is ...

... 100 = 2²×5²

The number of divisors of 100 is the product of the exponents of these factors, after each has been increased by 1: (2+1)(2+1) = 9. Those divisors are ...

... 1, 2, 4, 5, 10, 20, 25, 50, 100

A rectangle can be formed with each divisor as the length of a side. If we count 1×100 and 100×1 as the same rectangle, then 5 different rectangles are possible:

... 1×100, 2×50, 4×25, 5×20, 10×10

_____

On the other hand, the prime factorization of 55 is ...

... 55 = 5¹×11¹

This means the number of divisors is (1+1)(1+1) = 4. Those divisors are ...

... 1, 5, 11, 55

The number of rectangles that can be formed from these is 2:

... 1×55, 5×11

100 has more divisors, so there are more ways that rectangles can be formed from them.

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Ivan

Answer:

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nevsk [136]
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8 0
4 years ago
Someone help me on this one
juin [17]

It's an isosceles triangle, so the angles at the base are congruent:


m\anlge WXY=m\angle WZY


The triangle XYW is a rectangular triangle.


We know that the sum of the measures of angles in a triangle is 180°.


Therefore we have the equation:


m\angle YWZ+90^o+17^o=180^o\\\\m\angle YWZ+107^o=180^o\ \ \ |-107^o\\\\m\angle YWZ=73^o



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Answer:


Step-by-step explanation:

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3) ((a^{2})^{-2})^{2}=(a^{-4})^{2}=(a^{-8})

4) (a*a)^{2} =  (a^{2})^{2}=a^{4}

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