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2 years ago

Solve the equation 144x²-1=0

Mathematics

1 answer:

ratelena [41]2 years ago

8 0

x=0.083333,−0.083333

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A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Portland. The stu

iVinArrow [24]

Answer:

$-0.061 < P_1 -P_2< 0.025$

Step-by-step explanation:

Give data:

$n_1 = 350$

$n_2 =250$

$x_1 = 23$

$x_2 = 21$

$\hat{P} 1 = \frac{x_1}{n_1} = \frac{23}{350} = 0.066$

$\hat{P} 2 = \frac{x_2}{n_2} = \frac{21}{250} = 0.084$

for 95% confidence interval

$\alpha = 1 - 0.95 = 0.05 and \alpha/2 = 0.025$

$z_{\alpha/2} = 1.96$ from standard z- table

confidence interval for P_1 and P_2 is

$\hat{P} 1 - \hat{P} 2 \pm z_{\alpja/2} \sqrt{\frac{\hat{P} 1(1-\hat{P} 1)}{n_1} +\frac{\hat{P} 2(1-\hat{P} 2)}{n_2}}$

$(0.066 - 0.084) \pm 1.96 \sqrt{\frac{0.066(1-0.066)}{350} +\frac{0.084(1-0.084)}{250}}$

$-0.018 \pm 0.043$

confidence interval is

$-0.018 - 0.043 < P_1 -P_2$

$-0.061 < P_1 -P_2< 0.025$

7 0

2 years ago

To make sure that a given parallelogram is a rectangle, at least how many of

jeka94

Answer:

it can be either all or none

Step-by-step explanation:

because if you have one it will be off set just trust me.

7 0

2 years ago

(6.04)The scatter plot shows the relationship between the number of hours spent jogging and the number of minutes spent stretchi

DENIUS [597]

The y int is where the line crosses the y axis...it is (0,1)...or just 1

1 minute, the number of minutes students stretch when they do not jog

5 0

3 years ago

Read 2 more answers

Find the length of the third side. If necessary, round to the nearest tenth.

viva [34]

Answer:

the question states if necessary, round the nearest tenth and by using the pythagoras theorem the answer should be 10 since its 9.21 and its nearest 10th is 10? im not quite sure though

5 0

1 year ago

Read 2 more answers

Two cross roads ,each width 10m cut at right angle through the centre of a rectangular park of length 700m and breadth 300m and

Dafna11 [192]

Answer:

Step-by-step explanation:

Area of one road = 700 x 10

7000 sq m

area of another road

= 300 x 10 = 3000sq m

Total area of road

= 7000 + 3000 - 10 x 10

= 9900 sq m

Area of park

= 700 x 300

= 210000 sq m

less area of road

= 210000 - 9900

= 200100 sq m

= 200100 / 10000 hectare

= 20.01 hectare.

7 0

2 years ago