Anytime you have a triangle (right triangles are preferred) where at least 2 angle measures and 1 side is known. Or, at least two sides and 1 angle measure.
OR..... 3 sides or three angles are known. So, sines or cosines could be used at almost anytime to find the sides and angles of a triangle!
Answer:
Step-by-step explanation:
Find attached:
For algebraic division use KCF method.
K - Keep the first fraction
C- Change division to multiplicatin
F -Flip the second fraction.
3) Indenty used: (a -b)² =a² -2ab + b²
Where a = m and b =2
4) Identity used: (a +b)² = a² + 2ab +b²
Where a = w and b = 1
5) Identity used: a² - b² = (a +b)*(a -b)
Where a = z and b = 2
Answer:
2
Step-by-step explanation:
Ok so 40y2/50y3.... you are going to cancel out the common factor (10)
4y2/5y3..
now apply the exponent rule, which is : xa /xb = 1/ xb-a
so...y2/y3 = 1/ y3 - 2 = 1/y
ANSWER : 4/5y