Answer:
Step-by-step explanation:
x/4 - y/3 = 1..multiply everything by the LCD....which is 12
3x - 4y = 12 <== standard form
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if it makes it easier for u, x/4 is the same as (1/4)x and y/3 is the same as (1/3)y
so ur problem can be written as : (1/4)x - (1/3)y = 1....multiply by 12
12(1/4)x - 12(1/3)y = 12(1)
(12/4)x - (12/3)y = 12.....reduce
3x - 4y = 12
Using derivatives, it is found that:
i) 
ii) 9 m/s.
iii) 
iv) 6 m/s².
v) 1 second.
<h3>What is the role of derivatives in the relation between acceleration, velocity and position?</h3>
- The velocity is the derivative of the position.
- The acceleration is the derivative of the velocity.
In this problem, the position is:
item i:
Velocity is the <u>derivative of the position</u>, hence:
Item ii:
The speed is of 9 m/s.
Item iii:
Derivative of the velocity, hence:
Item iv:
The acceleration is of 6 m/s².
Item v:
t for which a(t) = 0, hence:
Hence 1 second.
You can learn more about derivatives at brainly.com/question/14800626
Answer:
A. 76
B. 150
C. 38
Step-by-step explanation:
SOLUTION:
To begin with, let's establish that the formula of this line is in slope-intercept form as follows:
y = mx
The formula for this line isn't:
y = mx + b
This is as this line doesn't have a y-intercept ( b ) as it passes through the origin instead. This means that ( b ) would be rendered useless in this formula as it would just bring us back to the y = mx formula as displayed below:
y = mx + b
y = mx + 0
y = mx
Moving on, for ( m ), we need to find the gradient of the line as displayed below:
m = gradient
m = rise / run
m = 10 / 2
m = 5
Now, we must simply substitue ( m ) into the formula in order to obtain the equation for this line as displayed below:
y = mx
y = 5x
Therefore, the answer is:
A. y = 5x
If we plot the data on the graph, we can see that the
data is skewed to the right (positive skew) and there is an outlier. In skewed
data and presence of outlier, the median is most commonly used measure of
central tendency. This is because a positive skew would result in a positive
bias to the mean. Meaning that it would be a lot larger than the median and not
really representing the actual central tendency. The median however is less
affected by the skew and outliers.
Answer: Median, because the data are skewed and there is
an outlier
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