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Leokris [45]
3 years ago
14

Assuming there’s is a proportional relationship which additional set of values could be included in the table

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0

Answer:

I don't know

Step-by-step explanation:I need the answer

Arisa [49]3 years ago
3 0

Answer:

The answer you are looking for is A

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

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A (5-x) = bx - 8<br> x =
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Find the median of these numbers 5,9,13,7,5,7
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Answer:

The mean is 7

Step-by-step explanation:

5,5,7,7,9,13

9-7 is going to get 7

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Nancy created a graph to predict the pay she will take home after taxes are taken from her income. Using the information on the
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A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long
Pie

Answer:

Surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

S = \frac{1}{2}pl+B                                       ...... (1)

Here, p represents the perimeter of the base , l the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid(l) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = 3 \times (side)

                                                          = 3 \times 20 = 60 inches

Area of equilateral triangle(B) = \frac{\sqrt{3} }{4} \times (side)^{2}

                                                 =\frac{\sqrt{3} }{4} \times (20)^2 = 100\sqrt{3}  square inches.

Substitute the above values in equation (1) as shown below:

S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}

S= 390+100\sqrt{3} square inches

Hence, the surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches.

6 0
2 years ago
Please help me with this question.
oksano4ka [1.4K]

Answer:

the centroid i believe...

3 0
3 years ago
Read 2 more answers
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