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maks197457 [2]
3 years ago
9

10.222 in a fraction

Mathematics
1 answer:
liq [111]3 years ago
8 0
5111/500 or 10 111/500
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Help!!!!!!!!!!!!!!!!!
Zielflug [23.3K]

Answer:

sorry but im guessing this i think it is no.1

Step-by-step explanation:

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3 years ago
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I need help solving parallel and perpendicular lines.
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Parell lines are that do not intersect and perpendicular are that make a 90% angle

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2 years ago
3/4 divided by 1/5 PLEASE ANSWER
sergejj [24]

Answer:

3.75

Step-by-step explanation:

To make it a fraction form answer, you multiply the dividend numerator by the divisor denominator to make a new numerator.

Furthermore, you multiply the dividend denominator by the divisor numerator to make a new denominator:

To make the answer to 3/4 divided by 1/5 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:

15/4 = 3.75

The answer is rounded to the nearest four decimal points if necessary.

15/4 is an improper fraction and should be written as 3 3/4.

 

 

3 0
2 years ago
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NEED ANSWER RIGHT NOW PLS Which graph represents the solution set of the inequality Negative 9 greater-than x?
Agata [3.3K]

Answer:

i think C

Step-by-step explanation:

tell me if i am wrong and hope you have a good day

3 0
2 years ago
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The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili
Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

\lambda= 4.5

Formula:

P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}

a) No accidents occur in one week.

P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111

b) 5 or more accidents occur in a week.

P( x \geq 5) = 1-\displaystyle \sum P(x

c) One accident occurs today.

The mean number of accidents per day is given by

\lambda = \dfrac{4.5}{7} = 0.64

P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747

5 0
2 years ago
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