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3 years ago

10.222 in a fraction

Mathematics

1 answer:

liq [111]3 years ago

8 0

5111/500 or 10 111/500

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I need help on number 11-13 please

schepotkina [342]

The answer to number 13 is141

8 0

3 years ago

Please help. Thank you.

damaskus [11]

(10x + 4) + (5x-4) ≈ 180

solve for x and you get x≈12

plug 12 in to 5x-4 and you get 56

7 0

4 years ago

Select the correct answer from each drop-down menu.

ohaa [14]

Answer:

y = -x + 17

Step-by-step explanation:

A(-10,-3)

B(7,14)

C(5,12)

Need line CD perpendicular to AB through C.

Solution:

slope of AB, m1 = (yb-ya) / (xb-xa) = (14- -3) / (7- -10) = 17/17 = 1

Slope of CD, m2 = -1/m1 = -1 / 1 = -1

Line CD through C, using the point slope form

y-yc = m2(x-xc)

y-12 = -1 (x-5)

rearrange

y = -x + 5 + 12

y = -x + 17

5 0

3 years ago

These two lines intersect at<br> (4, -2)<br> No solution<br> (-2, 4)<br> (4, 2)

umka2103 [35]

Answer:

the lines intersect at (4,-2)

3 0

3 years ago

A lake is 200 feet wide. Two boats start to move towards one another from opposite shores. In one minute, the first boat goes 40

NARA [144]

Answer:

I use faction

Step-by-step explanation:

The first boat.

$\frac{40 feet}{60 seconds}$ ÷ 10 = $\frac{4 feet}{6 seconds}$

$\frac{4 feet}{6 seconds}$ ÷ 2 = $\frac{2 feet}{3 seconds}$

The first boat move $\frac{2 feet}{3 seconds}$

The second one do the same

$\frac{30 feet}{60 seconds}$ ÷ 10 = $\frac{3 feet}{6 seconds}$

$\frac{3 feet}{6 seconds}$ ÷ 2 = $\frac{1.5 feet}{3 seconds}$

That is the speed of each boat.

The first boat need 50 minutes to get to the other side

2000 ÷ 2 =1000

1000 x 3 = 3000

3000 ÷ 60 = 50

The second boat need 66.6666666667 minutes to get to the other side

200 ÷1.5 = 1333.33333333

1333.33333333 x 3 = 4000

4000 ÷ 60 = 66.6666666667

8 0

3 years ago