Substitute the f(x) and g(x) following the required operations:
A. (f+g)x = (x^2 + 1) + (x + 1) = x^2 + x + 2
B. (f-g)x = (x^2 + 1) - (x + 1) = x^2 - x
C. (fg)x = (x^2 + 1)(x + 1) = x^3 + x^2 + x + 1
D. (f/g)x = (x^2 + 1) / (x + 1) or x - 1 + 2/(x+1) if answer must be in expanded form
E. (f o g)x = (x+1)^2 + 1 = x^2 + 2x + 2
F. (g o f)x = (x^2 + 1) + 1 = x^2 + 2
Answer:
The sum of three integers is 280.
a + b + c = 280
;
The sum of the first and second integers exceeds the third by 70.
a + b = c + 70
:
the third integer is 21 less than the first.
c = a - 21
:
Rearrange the 2nd equation and use elimination with the 1st equation
a + b + c = 280
a + b - c = 70
------------------subtraction eliminates a & b, find c
0 + 0 + 2c = 210
c = 210/2
c = 105
then
105 = a - 21
a = 105 + 21
a = 126
Find b using the 1st equation
126 + b + 105 = 280
b = 280 - 231
b = 49
:
:
See if that checks out
126 + 49 + 105 = 280
:
the three integers. 126, 49, 105
Working shown, hopefully it helps
