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tester [92]
2 years ago
11

write two equations that when graphed look like this *see image*. please help its due soon and i will give ya 75 points for answ

ering CORRECTLY thanks, 5 stars, and brainlist. thank

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
4 0

The graph is showing the equation of circle x²+y²=4

<h3>What is a circle?</h3>

A circle is a two-dimensional geometry on the plane having a centre point and the circular line is drawn equidistant from the centre point.

The given graph in the question represents the equation of the circle cutting the points on the x-axis and y-axis at 4 which is the radius of the circle.

The equation will be as follows:-

x²+y²=4

Hence the graph is showing the equation of circle x²+y²=4

To know more about circles follow

brainly.com/question/24375372

#SPJ1

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Is it ever possible that cos (A−B)=cos ⁡A−cos ⁡B? Why
svetlana [45]

Answer:

  yes, there are an infinite number of solutions

Step-by-step explanation:

The attached graph shows values of A and B (x and y) that can make this equation be true. Any of the points on any of the curves will satisfy the equation. (The repetition continues indefinitely in all directions.)

8 0
3 years ago
3(x-5)=2(x-10)<br> Solce for X
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Answer: X = -5

Step-by-step explanation:

3(x-5)=2(x-10)

3x - 15 = 2x -20

3x = 2x -5

x = -5

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A quadrilateral has its four points at the coordinates (1,1) , (-3,1) , (1,4) , &amp; (-3,4). What type of quadrilateral is it?
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3 0
3 years ago
Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su
777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

a, ar, ar^2,...\\a  = 7\\r = 7

7, 7^2, 7^3, 7^4...

Sum of n terms in a geometric progression:

S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}

For sum of five terms, we put n= 5, a = 7, r = 7

S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607

The sum of first five term of GP is 19607.

Verification:

2801\times 7 = 19607

Thus, the sum is equal to product of 2801 and 7.

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