Question

A flyer is spread by people at a large conference. Within one hour, the first person gives a stack of flyers to six people. Within the next hour, those six people give a stack of flyers to six new people. If this pattern continues, which summation can be used to calculate the number of people who receive a stack of flyers, not including the initial person, in the first five hours?
Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1
Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 1 (6) Superscript n minus 1
Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n
Sigma-Summation Underscript n = 1 Overscript 4 EndScripts 1 (6) Superscript n

Answer 1

Answer:

ANSWER IS A ON EDGE 2020

Step-by-step explanation:

hope this helps!!!

Answer 2

Answer:

In summation form $\sum_{n = 1} ^{5} 6(6)^{n - 1}$

Step-by-step explanation:

Within one hour, the first person gives a stack of flyers to six people and within the next hour, those six people give a stack of flyers to six new people.

So, in the first 5 hours, the summation of people that receive a stack of flyers not including the initial person will be given by

6 + (6 × 6) + (6 × 6 × 6) + (6 × 6 × 6 × 6) + (6 × 6 × 6 × 6 × 6).

So, in summation form $\sum_{n = 1} ^{5} 6(6)^{n - 1}$

Therefore, Sigma-Summation Underscript n = 1 Overscript 5 EndScripts 6 (6) Superscript n minus 1, gives the correct solution. (Answer)