Answer:
Let the cost of orange be X and cost of cherry be y
3x + 9y = 78
8x + 4y = 58
Solving equation using elimination method
multiplying eq 1 with 8 and eq 2 with 3
8(3x + 9y ) = 78(8)
3( 8x + 4y) = 3(58)
24x + 72 y = 624
24x + 12y = 174
subtracting,
60 y = 450
y = 7.5
3x + 9(7.5) = 78
3x + 67.5 = 78
3x = 78 - 67.5
3x = 10.5
x = 3.5
<h2>Box of orange = $3.5 </h2><h2>Box of cherry = $7.5</h2>
Given:
The cost of each carnival ticket is $5.
To find:
The equation, table of values and graph for the given problem.
Solution:
Let x be the number of tickets and y be the total money spent on tickets.
Cost of one ticket = $5
Cost of x tickets = $5x
So, total cost is

The required equation is
.
At x=1,


At x=2,


At x=3,


The required table of values is
x y
1 5
2 10
3 15
So, the required table of values is table A.
From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.
So, the required graph is graph B.
Since the required answers are
, table A, graph B, therefore the correct option is B.
9 and 3. Because 9 is a composite number (3*3 = 9) and 3 is a composite number (1*3 = 3).