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3 years ago

Plz help ❤️ 2 questions worth 13 points! Thanks!! :)))

Mathematics

1 answer:

bazaltina [42]3 years ago

8 0

Question 1 might be B. 0.3

Question 2 might be D.TW, TM, CW, CM, HW, HM

I'm not 100% sure though

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Combine the following sets of terms.

DanielleElmas [232]

Let's simplify step-by-step To understand :)

3x2−7x−(x2+3x−9)

Distribute the Negative Sign:

=3x2−7x+−1(x2+3x−9)

=3x2+−7x+−1x2+−1(3x)+(−1)(−9)

=3x2+−7x+−x2+−3x+9

Combine Like Terms:)

=3x2+−7x+−x2+−3x+9

=(3x2+−x2)+(−7x+−3x)+(9)

=2x2+−10x+9

Answer :)

=2x2−10x+9

HOPE THIS HELPS

3 0

3 years ago

The relation ((6, 8), (7, 10), (7, 12), (8, 16),

Brilliant_brown [7]

Answer:

x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

Step-by-step explanation:

Given the relation

{(6, 8), (7, 10), (7, 12), (8, 16), (10, 16)}

We know that a relation is a function that has only one output for any unique input.

As the inputs or x-values of the relations are:

at x = 6, y = 8

at x = 7, y = 10

at x = 7, y = 12

at x = 8, y = 16

at x = 10, y = 16

If we closely observe, we can check that there is a repetition of x values.

i.e. x = 7 is repeated twice.

Hence, there is NO MORE unique input. We can not have repeated inputs.

Thus, the relation is NOT a function.

8 0

3 years ago

ASAP! GIVING BRAINLIEST! Please read the question THEN answer correctly! No guessing. Show your work or give an explaination.

lorasvet [3.4K]

Answer:

Step-by-step explanation:

A function has at most one y value for every x value. This means that for every vertical line, there can be at most one intersection.

This example clearly doesn't satisfy this requirement.

6 0

3 years ago

Amy's grandmother gave her 3 identical chocolate chip cookies and 4 identical sugar cookies. In how many different orders can Am

Dmitrij [34]

Answer:

chocolate chip cookie first: 15 ways

chocolate chip cookie last: 15 ways

chocolate chip cookie first and last: 5 ways

Step-by-step explanation:

There is a total of 7 cookies.

Is she eats a chocolate cookie first, she will have 2 chocolate cookies and 4 sugar cookies (6 in total).

So, to find the number of different orders that Amy can eat the remaining cookies, we just need to calculate a combination of 6 choose 2 (that is, the number of ways we can put the 2 chocolate cookies among the 6 cookies) or a combination of 6 choose 4 (same thing, but for the sugar cookies):

C(6,2) = 6! / (2! * 4!) = 6 * 5 / 2 = 15 ways

Is she eats a chocolate cookie last, she will have 2 chocolate cookies and 4 sugar cookies (6 in total), so the problem is solved again with a combination of 6 choose 2:

C(6,2) = 15 ways

Is she eats a chocolate cookie first and last, she will have just 1 chocolate cookie left and 4 sugar cookies (5 in total), so the problem is solved with a combination of 5 choose 1 or a combination of 5 choose 4:

C(5,1) = 5! / (1! * 4!) = 5 ways

6 0

3 years ago

The length of a vegetable garden is 4 feet longer than its width. If the area of the garden is 140 square feet, find its dimensi

Lena [83]

Length is 14 and the width is 10

4 0

3 years ago