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ruslelena [56]
3 years ago
11

Plz help ❤️ 2 questions worth 13 points! Thanks!! :)))

Mathematics
1 answer:
bazaltina [42]3 years ago
8 0

Question 1 might be B. 0.3

Question 2 might be D.TW, TM, CW, CM, HW, HM

I'm not 100% sure though

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7 men have 7 wives.
serg [7]

Answer:

98 is your answer

Step-by-step explanation:

6 0
2 years ago
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The price of a gym membership has a one-time sign-up fee and a monthly fee. The price can be modeled by the function y = 10x + 1
monitta
15; it represents the one-time sign-up fee

The y-intercept can be found either on the graph where the line intercepts the y-axis, or b in the equation y=mx+b.

It represents the fee because it will be charged even if the number of months (x) is zero. 10 is the monthly fee because it is multiplied by x, the number of months.
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ILL GIVE BRAINLESS PLS HELP
Elina [12.6K]
X is greater than or equal to 67

1000/15 =66.6 =67
6 0
2 years ago
Can 12/15 be simplify
Semmy [17]
Yes 12/15 can be simplified. 

To simplify 12/15 find the greatest common multiple. The <span> greatest common multiple of 12/15 is 3. Now divide 12/15 by 3. 
</span>
12 ÷ 3 = 4 
15 ÷ 3 = 5 

4/5 is the simplified version of 12/15


6 0
3 years ago
are any two regular polygons similar. The area of the smaller figure is about 390 cm^2. choose the best estimate of the area of
galben [10]

Answer:

The best estimate of the area of the larger figure is 693\ cm^{2}

Step-by-step explanation:

step 1

<em>Find the scale factor</em>

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x-----> the corresponding side of the larger figure

y-----> the corresponding side of the smaller figure

so

z=\frac{x}{y}

we have

x=12\ cm

y=9\ cm

substitute

z=\frac{12}{9}=\frac{4}{3} -----> the scale factor

step 2

<em>Find the area of the larger figure</em>

we know that

If two figures are similar, then the ratio of its  areas is equal to the scale factor squared

Let

z----> the scale factor

x-----> the area of the larger figure

y-----> the area of the smaller figure

so

z^{2}=\frac{x}{y}

we have

z=\frac{4}{3}

y=390\ cm^{2}

substitute and solve for x

(\frac{4}{3})^{2}=\frac{x}{390}

(\frac{16}{9})=\frac{x}{390}

x=390*16/9=693.33\ cm^{2}

4 0
2 years ago
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