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Gelneren [198K]

3 years ago

9

You deposit $1500 in an account that pays 7% annual interest. Find the balance after 2 years when the interest is compounded dai

ly.

1 answer:

just olya [345]3 years ago

3 0

A = $ 1,721.28

A = P + I where

P (principal) = $ 1,500.00

I (interest) = $ 221.28

You might be interested in

Which points are 4 units apart?

xz_007 [3.2K]

The points that are 4 units apart are B and D

<h3>Complete question</h3>

Which points are 4 units apart? On a coordinate plane, point A is at (-2, 4), point B is at (3, -6), point C is at (-1, 0), point D is at (3, -2).

B and C

C and D

A and C

B and D

<h3>How to determine the points?</h3>

To do this, we simply calculate the distance using the following equation

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2$

Using the given points, we have:

$BC = \sqrt{(3+ 1)^2 + (-6 -0)^2} = 7.2$

$CD = \sqrt{(-1 - 3)^2 + (0 +2)^2} = 4.5$

$AC = \sqrt{(-2 + 1)^2 + (4 -0)^2} = 4.1$

$BD = \sqrt{(3 - 3)^2 + (-6 +2)^2} = 4$

Hence, the points that are 4 units apart are B and D

Read more about distance at:brainly.com/question/15821277

#SPJ1

3 0

2 years ago

Two lines that are skew can be parallel

sveticcg [70]

Answer: skew lines are two lines that do not intersect and are not parallel

Step-by-step explanation:

3 0

3 years ago

What is the solution for these lines<br> (line a ) x+2y=4<br> (line b ) 3x-2y=4

Amanda [17]

X+2y=4
3x-2y=4
4x=8
x=2
2+2y=4
2y=2
y=1

y=1
x=2

Hope this helps :)

3 0

3 years ago

Read 2 more answers

Write y=-3/4 x-2 in standard form using integers.

jeyben [28]

Standard form is Ax + By = C

y = (-3/4)x - 2

Multiply both sides by 4.

4y = -3x - 8

Add 3x on both sides

3x + 4y = -8

Your final answer is 3x + 4y = -8.

8 0

3 years ago

Please help!!As soon as possible!!

pychu [463]

Answer: Their equations have different y-intercept but the same slope

Step-by-step explanation:

Since, the slope of the line passes through the points (2002,p) and (2011,q) is,

$m_1 = \frac{q-p}{2011-2002} = \frac{q-p}{9}$

Similarly, the slope of the line asses through the points (2,p) and (11,q) is,

$m_2 = \frac{q-p}{11-2} = \frac{q-p}{9}$

Since, $m_1 = m_2$

Hence, both line have the same slope.

Now, the equation of the line one having slope $m_1$ and passes through the point (2002,p) is,

$y - p = \frac{q-p}{9}(x-2002)$

Put x = 0 in the above equation,

We get, $y = \frac{2000(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2000(p-q)}{9}+p)$

Also, the equation of second line having slope $m_2$ and passes through the point (2,p)

$y-p=\frac{q-p}{9}(x-2)$

Put x = 0 in the above equation,

We get, $y = \frac{2(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2(p-q)}{9}+p)$

Thus, both line have the different y-intercepts.

⇒ Third option is correct.

6 0

3 years ago