50 + x ≥ 268
X ≥ 218
STEP BY STEP WORK
50 + x ≥268
-50 -50
x ≥218
Jan needs to save at least $218 for camp
Hope I helped :)
You should get the app "photomath" that will help out alot!!!
9514 1404 393
Answer:
A, M, N, F
Step-by-step explanation:
I find it easier to look at the graph, rather than mess with the coordinate transformations. Each image point is the same distance from the line of reflection that its pre-image point is. The line joining the two points is perpendicular to the line of reflection.
See attached for the reflected points.
__
The red and turquoise dashed lines are the lines y=x and y=-x, respectively. The same-colored arrows show the reflection of the relevant point.
_____
The transformations of interest are ...
(x, y) ⇒ (y, x) . . . . reflection over y = x
(x, y) ⇒ (-x, y) . . . . reflection over y-axis
(x, y) ⇒ (x, -y) . . . . reflection over x-axis
(x, y) ⇒ (-y, -x) . . . . reflection over y = -x
I think it’s the first one , sorry if i’m wrong
Answer:
0.40
Step-by-step explanation:
Members who run only long distance = 8%
So, probability that a member will run only long distance = P(A) = 0.08
Members who compete only in field events = 32%
So, probability that a member will compete only in field events = P(B) 0.32
Members who are sprinters = 12%
So, probability that a member is sprinter = P(C) 0.12
We have to calculate the probability that a randomly chosen team member runs only long-distance or competes only in field events. i.e we have to find P(A or B). Since these events cannot occur at the same time, we can write:
P(A or B) = P(A) + P(B)
Using the values, we get:
P(A or B) = 0.08 + 0.32 = 0.40
Thus, the probability that a randomly chosen team member runs only long-distance or competes only in field events is 0.40
