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lawyer [7]
3 years ago
5

Higher Current = ________ Moving Electric Charges (Electrons) *

Physics
1 answer:
Eva8 [605]3 years ago
7 0

Answer:

Higher current is normally achieved by faster moving electrons.

Explanation:

  • Current is solely not the speed of the electric charges, but speed of the electrons is one of the factors that current depends on.
  • Current is the net charge flowing per unit time.
  • Current can be represented by:

            I=v×e×N×A

where,

                  I= current

                  e= electric charge

                  v= speed of electrons

                  N=no. of free electric charges per volume

  • The unit of current is Ampere, represented by A. It is flow of 1 coulomb of charge in 1 second.
You might be interested in
In an RL series circuit, an inductor of 3.54 H and a resistor of 7.76 Ω are connected to a 26.6 V battery. The switch of the cir
podryga [215]

Answer:

Energy stored in inductor will be 20.797 J

Explanation:

We have given inductance L = 3.54 H

And resistance R = 7.76 ohm

Battery voltage V = 26.6 VOLT

After very long time means at steady state inductor behaves as short circuit

So  current i=\frac{V}{R}=\frac{26.6}{7.76}=3.427Amp

Now energy stored in inductor E=\frac{1}{2}Li^2=\frac{1}{2}\times 3.54\times 3.427^2=20.797J

So energy stored in inductor will be 20.797 J

4 0
4 years ago
What happens to an electromagnetic waves as it passes from space to matter
sertanlavr [38]

Interaction of Electromagnetic Radiation and Matter

It is well known that all matter is comprised of atoms. But subatomically, matter is made up of mostly empty space. For example, consider the hydrogen atom with its one proton, one neutron, and one electron. The diameter of a single proton has been measured to be about 10-15 meters. The diameter of a single hydrogen atom has been determined to be 10-10meters, therefore the ratio of the size of a hydrogen atom to the size of the proton is 100,000:1. Consider this in terms of something more easily pictured in your mind. If the nucleus of the atom could be enlarged to the size of a softball (about 10 cm), its electron would be approximately 10 kilometers away. Therefore, when electromagnetic waves pass through a material, they are primarily moving through free space, but may have a chance encounter with the nucleus or an electron of an atom.

Because the encounters of photons with atom particles are by chance, a given photon has a finite probability of passing completely through the medium it is traversing. The probability that a photon will pass completely through a medium depends on numerous factors including the photon’s energy and the medium’s composition and thickness. The more densely packed a medium’s atoms, the more likely the photon will encounter an atomic particle. <span>In other words, the more subatomic particles in a material (higher Z number), the greater the likelihood that interactions will occur  </span>Similarly, the more material a photon must cross through, the more likely the chance of an encounter.

When a photon does encounter an atomic particle, it transfers energy to the particle. The energy may be reemitted back the way it came (reflected), scattered in a different direction or transmitted forward into the material. Let us first consider the interaction of visible light. Reflection and transmission of light waves occur because the light waves transfer energy to the electrons of the material and cause them to vibrate. If the material is transparent, then the vibrations of the electrons are passed on to neighboring atoms through the bulk of the material and reemitted on the opposite side of the object. If the material is opaque, then the vibrations of the electrons are not passed from atom to atom through the bulk of the material, but rather the electrons vibrate for short periods of time and then reemit the energy as a reflected light wave. The light may be reemitted from the surface of the material at a different wavelength, thus changing its color.

<span>X-Rays and Gamma Rays
</span>X-rays and gamma rays also transfer their energy to matter though chance encounters with electrons and atomic nuclei. However, X-rays and gamma rays have enough energy to do more than just make the electrons vibrate. When these high energy rays encounter an atom, the result is an ejection of energetic electrons from the atom or the excitation of electrons. The term "excitation" is used to describe an interaction where electrons acquire energy from a passing charged particle but are not removed completely from their atom. Excited electrons may subsequently emit energy in the form of x-rays during the process of returning to a lower energy state.

3 0
3 years ago
What is, by far, the most abundant component of Earth’s atmosphere?
Serjik [45]

Answer:

Molecular Nitrogen

Explanation:

Earth's atmosphere is a mixture of several gases in their molecular form . The most abundant of them is the element nitrogen. 78% of it is nitrogen and the rest that follow are Oxygen, Carbon dioxide and a mixture of other gases like Neon, Helium, Methane, Water vapor. hen the air is dry, argon is the third most abundant element in the earth's atmosphere.

As the height above the earth's surface increases, the air molecules decrease.

5 0
3 years ago
Two capacitors, C1 = 25.0 μF and C2 = 31.0 μF, are connected in series, and a 6.0-V battery is connected across them.a. Find the
Brrunno [24]

Answer:

13.83928\times 10^{-6}\ F

249.10704\times 10^{-6}\ J

137.89848\times 10^{-6}\ J

111.20842\times 10^{-6}\ J

2.98273 V

Explanation:

C_1=25\ mu F

C_2=31\ mu F

V = Voltage = 6 V

Equivalent capacitance is given by

\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}\\\Rightarrow C=\dfrac{C_1C_2}{C_1+C_2}\\\Rightarrow C=\dfrac{25\times 10^{-6}\times 31\times 10^{-6}}{(25+31)\times 10^{-6}}\\\Rightarrow C=13.83928\times 10^{-6}\ F

Equivalent capacitance is 13.83928\times 10^{-6}\ F

Energy stored is given by

E=\dfrac{1}{2}CV^2\\\Rightarrow E=\dfrac{1}{2}\times 13.83928\times 10^{-6}\times 6^2\\\Rightarrow E=249.10704\times 10^{-6}\ J

Total energy stored is 249.10704\times 10^{-6}\ J

Charge is given by

Q=CV\\\Rightarrow Q=13.83928\times 10^{-6}\times 6\\\Rightarrow Q=83.03568\times 10^{-6}\ C

Voltage is given by

V_1=\dfrac{Q}{C_1}\\\Rightarrow V_1=\dfrac{83.03568\times 10^{-6}}{25\times 10^{-6}}\\\Rightarrow V_1=3.3214272\ V

E_1=\dfrac{1}{2}C_1V_1^2\\\Rightarrow E_1=\dfrac{1}{2}\times 25\times 10^{-6}\times 3.3214272^2\\\Rightarrow E_1=137.89848\times 10^{-6}\ J

Energy strored in C1 is 137.89848\times 10^{-6}\ J

V_2=\dfrac{Q}{C_2}\\\Rightarrow V_2=\dfrac{83.03568\times 10^{-6}}{31\times 10^{-6}}\\\Rightarrow V_2=2.67857\ V

E_2=\dfrac{1}{2}C_2V_2^2\\\Rightarrow E_2=\dfrac{1}{2}\times 31\times 10^{-6}\times2.67857^2\\\Rightarrow E_2=111.20842\times 10^{-6}\ J

Energy stored in C2 is 111.20842\times 10^{-6}\ J

E=E_1+E_2\\\Rightarrow E=137.89848\times 10^{-6}+111.20842\times 10^{-6}\\\Rightarrow E=249.107\times 10^{-6}\ J

So, the energy is equivalent

Equivalent capacitance

C=C_1+C_2\\\Rightarrow C=25+31\\\Rightarrow C=56\times 10^{-6}\ F

E=\dfrac{1}{2}CV^2\\\Rightarrow V=\sqrt{\dfrac{2E}{C}}\\\Rightarrow V=\sqrt{\dfrac{2\times 249.107\times 10^{-6}}{56\times 10^{-6}}}\\\Rightarrow V=2.98273\ V

The voltage would be 2.98273 V

8 0
4 years ago
NEED Answer asap plz!!
stira [4]

Answer:

I think a is the right not clear but

7 0
3 years ago
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