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2 years ago

Which choice correctly describes what happens during heating?

Physics

1 answer:

Masja [62]2 years ago

7 0

Answer:

Option 4

Explanation:

During heating actually heat transfer takes place from a body at higher temperature to a body at lower temperature and the heat transfer takes place until both attain the same temperature

Therefore heat transfer depends on the temperature of the systems

Now while comparing the thermal energies of the systems, if both the systems have same mass then the system which is at higher temperature has greater thermal energy when compared to the system which is at lower temperature

So in this case assuming that both the systems have same mass then the energy will leave the system with greater thermal energy and go into the system with less thermal energy as the system with greater thermal energy in this case will be at higher temperature and we are considering this assumption because thermal energy not only depends on temperature but also depends on mass of the system

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The equation for density is mass divivded by volume.an increase in denstiy can result from all of following expect??

sineoko [7]

It would be option A (a decrease in mass with an increase in volume)

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2 years ago

An object on earth weighs 120 N. What is it’s mass ?

inna [77]

Weight = (mass) x (gravity)

120 N = (mass) x (9.8 m/s²)

Mass = (120 N) / (9.8 m/s²)

Mass = 12.24 kg (B)

7 0

2 years ago

Read 2 more answers

How does the work required to accelerate a particle from 10 m/s to 20 m/s compare to that required to accelerate it from 20 m/s

poizon [28]

To solve this problem we will apply the energy conservation theorem for which the work applied on a body must be equivalent to the kinetic energy of this (or vice versa) therefore

$W = \Delta KE$

$\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2$

Here,

m = mass

$v_{f,i}$ = Velocity (Final and initial)

First case) When the particle goes from 10m/s to 20m/s

$\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2$

$\Delta W = \frac{1}{2} (m)(20)^2 -\frac{1}{2} (m)(10)^2$

$W_1 = 150(m) J$

Second case) When the particle goes from 20m/s to 30m/s

$\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2$

$\Delta W = \frac{1}{2} (m)(30)^2 -\frac{1}{2} (m)(20)^2$

$W_1 = 250(m) J$

As the mass of the particle is the same, we conclude that more energy is required in the second case than in the first, therefore the correct answer is A.

5 0

2 years ago

The position-time equation for a certain train is xf=2.8m+(8.1m/s)t+(2.9m/s^2)t^2.

mash [69]

The formula without numbers is
$xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2}$
do the initial velocity would be
8.1 m/s
and the acceleration would be
2.9 m/s^2

3 0

2 years ago

Planets A and B have the same size, mass, and direction of travel, but planet

Luden [163]

Answer:

A. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are and respectively.

As masses are equal, so .

Similarly, let the radii of the planets A and B are and respectively.

As radii are equal, so .

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A,

my weight of planet B,

By using equations (i) and (ii),

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

Hence, option (A) is correct.

7 0

2 years ago