So, the final velocity of the ball when it is 10.0 m above the ground approximately <u>26.2 m/s</u>.
<h3>Introduction</h3>
Hi ! In this question, I will help you. This question uses the principle of final velocity in free fall. Free fall occurs only when an object is dropped (without initial velocity), so the falling object is only affected by the presence of gravity. In general, the final velocity in free fall can be expressed by this equation :

With the following condition :
- v = final velocity (m/s)
- h = height or any other displacement at vertical line (m)
- g = acceleration of the gravity (m/s²)
<h3>Problem Solving</h3>
We know that :
= initial height = 45.0 m
= final height = 10.0 m- g = acceleration of the gravity = 9.8 m/s²
Note :
At this point 10 m above the ground, the object can still complete its movement up to exactly 0 m above the ground.
What was asked :
- v = final velocity = ... m/s
Step by Step






<h3>Conclusion</h3>
So, the final velocity of the ball when it is 10.0 m above the ground approximately 26.2 m/s.
<h3>See More :</h3>
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We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.
You've already told us the speed in ft/s . It's right there in the question. You said that light travels about 982,080,000 ft/s.
We don't know how accurate that number is, but for purposes of THIS question, that's the number we're going with.
In scientific notation, it's written . . . <em>9.8208 x 10⁸ ft/s .</em>
We don't know where you were going with the number of seconds in a year. But to answer the question that you eventually asked, it turned out that we don't even need it.