Answer:
Explanation:
Here the rope is 10m long and making an angle of θ with the direction of canal or direction of flow of water in the canal .
sinθ = 2 / 10 = .2
θ = 11.5⁰
a )
Component of 500 N along the line perpendicular to the canal
= 500 sinθ
= 500 sin 11.5
= 100 N
b )
component of 500 N along the canal
= 500 cos 11.5
= 490 N approx .
Answer:
it will go up along the inclined plane by d = 9.62 m
Explanation:
As we know that puck is moving upward along the slide
then the net force opposite to its speed is given as

so here deceleration is given as

now plug in all values in it


now the distance covered by the puck along the plane is given as



KE = 1/2mv²
= 1/2(20 kg)(2m/s²)
= 1/2(20)(4)
= 1/2 (80)
KE = 40 J
hope this helps :)
Gravitational potential energy can be described as m*g*h (mass times gravity times height).
Originally,
15kg * 9.8m/s^2 *0.3 m = 44.1 kg*m^2/s^2 = 44.1 Joules.
After it is moved to a 1m shelf:
15kg * 9.8m/s * 1 = 147 kg*m^2/s^2= 147 Joules.
To find how much energy was added, we subtract final energy from initial energy:
147 J - 44.1 J = 102.9 Joules.