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3 years ago

What is, by far, the most abundant component of Earth’s atmosphere?

Physics

1 answer:

Serjik [45]3 years ago

5 0

Answer:

Molecular Nitrogen

Explanation:

Earth's atmosphere is a mixture of several gases in their molecular form . The most abundant of them is the element nitrogen. 78% of it is nitrogen and the rest that follow are Oxygen, Carbon dioxide and a mixture of other gases like Neon, Helium, Methane, Water vapor. hen the air is dry, argon is the third most abundant element in the earth's atmosphere.

As the height above the earth's surface increases, the air molecules decrease.

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Gibbons move through the trees by swinging from successive handholds, as we have seen. To increase their speed, gibbons may brin

Sedbober [7]

By bring their legs close to their bodies, they are decreasing the length of the pendulum which help them move more quickly.

A pendulum is nothing but a body suspended from a fixed point so that it can swing back and forth under the influence of gravity.

Here in this case Gibbons are bringing their legs close to their bodies and reducing the length of the pendulum. Since as the length of the pendulum increases the speed of the movement will be reduced. By bringing their legs close to their bodies they are reducing the length and in turn their speed increase and they move quickly.

To learn more about pendulum, visit here

brainly.com/question/14759840

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5 0

2 years ago

the power of a physicians eyes is 57.1 D while examinging a patient. how far from her eyes (in m) is the feature being examined.

yanalaym [24]

Answer:

14 cm

Explanation:

Power of eye = 57.1 D

The relation between the focal length and the power is

f = 1 / P = 1 / 57.1 = 0.0175 m = 1.75 cm

The distance between the image and the lens is, v = 2 cm

Let the distance between the object and the eye is u

Use the lens equation

1/ f = 1 / v - 1 / u

1 / 1.75 = 1 / 2 - 1 / u

1 / u = 1 / 2 - 1 / 1.75

1 / u = (1.75 - 2) / 3.5

u = - 14 cm

Thus, the distance between the feature and eye is 14 cm .

8 0

3 years ago

A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. if

AleksandrR [38]

? ? ? ? ? ? ? ? ? ? ?

8 0

4 years ago

A current loop ABCDA consists of a metal rod. a resistor R, and a pair of conducting rails separated by a distance d. The rod ha

Lilit [14]

Answer:

a) $\vec{d} =B-A$

b) $I=\frac{B*v*d*\sin 90 \textdegree}{R}$

c) $v \approx 0.6m/s$

Explanation:

From the question we are told that

Magnetic field strength $B=3.6T$

Distance traveled $d=7m$

Mass $m=4.7 kg$

Resistance $r=8.2 ohm$

Gravitational acceleration $g=9.8m/s^2$

$\theta =90 \textdegree$ Because of perpendicularity

Generally the direction of the current will be given as

$\vec{d} =B-A$

Because it opposes increases of magnetic flux

Generally the equation for induced EMF $E$ is mathematically given as

$E=B*v*d*\sin \theta$

$E=B*v*d*\sin 90 \textdegree$

Generally the equation for induced current $I$ is mathematically given as

$I=E/R$

$I=\frac{B*v*d*\sin 90 \textdegree}{R}$

Generally the the equation for force F at terminal speed is mathematically given as

$F=mg$

$mg=B*I*d*\sin 90 \textdegree$

$mg=B*(\frac{B * v * d }{R}) *d$

$v=\frac{m*g*R}{B^2*D^2}$

$v=\frac{4.7*9.8*8.2}{3.6^2*7^2}$

$v=0.59475m/s$

$v \approx 0.6m/s$

7 0

3 years ago

Two metal spheres of different sizes are charged such that the electric potential is the same at the surface of each. Sphere A h

vodka [1.7K]

Answer:

Explanation:

Given

Radius of A is twice of B i.e.

$R_A=2R_B$

Also Potential of both sphere is same

$V_A=V_B$

$V=\frac{kQ}{R}$

thus

$k\frac{Q_A}{R_A}=K\frac{Q_B}{R_B}$

$\frac{Q_A}{Q_B}=\frac{R_A}{R_B}$

$\frac{Q_A}{Q_B}=\frac{2}{1}=2$

$\frac{Q_B}{Q_A}=\frac{1}{2}$

(b)Ratio of $\frac{E_B}{E_A}$

Electric Field is given by $E=\frac{kQ}{R^2}$

thus $E_A=\frac{kQ_A}{R_A^2}$ ----1

$E_B=\frac{kQ_B}{R_B^2}$ ----2

Divide 2 by 1

$\frac{E_B}{E_A}=\frac{Q_B}{R_B^2}\times \frac{R_A^2}{Q_A}$

$\frac{E_B}{E_A}=\frac{1}{2}\times 4=2$

8 0

3 years ago