Fourths, then b. Sorry if late.
Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.
Isolate the x. Note the equal sign. What you do to one side you do to the other.
Subtract 2y from both sides
2x + 2y (-2y) = 10 (-2y)
2x = 10 - 2y
Isolate the x, divide 2 from both sides and from all terms.
(2x)/2 = (10 - 2y)/2
x = 5 - y
Place the variable in the front
x = -y + 5
x = -y + 5 is your answer
hope this helps
Answer:
It is a line with a positive slope and positive intercept
Step-by-step explanation:
If you want it in SF, -x + y = 4
Answer:
34
Step-by-step explanation:
F(x) = 2x^3 - 7x + 1
Let x= 3
F(3) = 2* 3^3 - 7*3 + 1
= 2 * 27 -21+1
= 54 -21 + 1
= 34
