Hey there!
So, if

, this would mean that we would do

and from this, we would get 8.
We will then need to find what is

.


=

So, the equation would really look like
. . .
![\left[\begin{array}{ccc} 8*(7)-2*4 = 48 \\ \\ x=\boxed{7}\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%208%2A%287%29-2%2A4%20%3D%2048%20%5C%5C%20%5C%5C%20x%3D%5Cboxed%7B7%7D%5Cend%7Barray%7D%5Cright%5D%20)
Hope this helps.
~Jurgen
-9 (5m+2) = 0
-45m - 18 = 0
+18 +18
-45m = 18
-45m/-45 = 18/-45
m= 0.4
Answer: 0.8238
Step-by-step explanation:
Given : Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with
and
.
Let x denotes the scores on a certain intelligence test for children between ages 13 and 15 years.
Then, the proportion of children aged 13 to 15 years old have scores on this test above 92 will be :-
![P(x>92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]](https://tex.z-dn.net/?f=P%28x%3E92%29%3D1-P%28x%5Cleq92%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B92-106%7D%7B15%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq%20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq-0.93%29%3D1-%281-P%28z%5Cleq0.93%29%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%5Cleq%20-z%29%3D1-P%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3DP%28z%5Cleq0.93%29%3D0.8238%5C%20%5C%20%5B%5Ctext%7BBy%20using%20z-value%20table.%7D%5D)
Hence, the proportion of children aged 13 to 15 years old have scores on this test above 92 = 0.8238
Answer: the large jar is cheaper
Step-by-step explanation:
If you divide the £1.54 by 440g and £1.26 by 340g, you'll find which one is cheaper per gram :
1.54/440 = 0.0035
1.26/340 = 0.0037
So, by comparing both prices/gram, you've found that the large jar is cheaper.