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CaHeK987 [17]
3 years ago
8

The vertices of quadrilateral EFGH are listed below.

Mathematics
1 answer:
pav-90 [236]3 years ago
6 0
It is going robe f help me ?
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Use the diagram and the value of x to find the measures of BCE and ECF.
stepan [7]

Answer:

125° and 55°

Step-by-step explanation:

∠ BCE and ∠ ECF are adjacent angles and are supplementary, thus

10x + 15 + 5x = 180, that is

15x + 15 = 180 ( subtract 15 from both sides )

15x = 165 ( divide both sides by 15 )

x = 11

Thus

∠ BCE = 10x + 15 = 10(11) + 15 = 110 + 15 = 125°

∠ ECF = 5x = 5(11) = 55°

7 0
3 years ago
TRUE OR FALSE <br>becomes zero for x=1<br>PLEASE HELP​
Vlad1618 [11]

Answer:

is this your only question?

5 0
2 years ago
PLEASE THINS IS DUE BY 1 P.M TODAY. PLEASE HELP ME
zaharov [31]

6 {x}^{2}  {y}^{2} (y + 3xy + 6x)
6 0
3 years ago
The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5
andreev551 [17]
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
4 0
2 years ago
What is the circumference of a circle with a<br> diameter of 3 cm? (Use 3.14 as pi)
hoa [83]

Answer:

circumference=9.42

Step-by-step explanation:

the formula for circumference is pi x diameter.

4 0
3 years ago
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