If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

Alternatively,

$\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}=\displaystyle \lim_{x\to\infty}\dfrac{3x^2+6}{x^2-4}\cdot\dfrac{1/x^2}{1/x^2}=\lim_{x\to\infty}\dfrac{3+\frac6{x^2}}{1-\frac4{x^2}} = \dfrac{3+0}{1-0}=\boxed{3}$

Hope this helps.

5 0

3 years ago

Janet's home went to Citizens Bank she borrowed 7000 at a rate of 8% the date of the alone was September 20th Janet Hope to repa

almond37 [142]

Interest depends a lot on the compounding period.
Since the period is exactly 4 months, we assume
APR=8%
monthly interest=8/12%=0.00666667
Interest due in 4 months
=7000[(1+0.08/12)^4-1]
=7000[0.0269345]
=$188.54

6 0

3 years ago