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Mrrafil [7]
3 years ago
9

Solve the equation 3(x+1 )-2=x+5

Mathematics
2 answers:
eimsori [14]3 years ago
8 0
The answer to the equation is x=2
Here’s how:

Paraphin [41]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

first, let's distribute.

3(x+1)-2=x+5

3x+3-2=x+5

then, let's combine like terms.

3x+1=x+5

now, we subtract x on both sides.

2x+1=5

subtract 1 on both sides.

2x=4

divide by 2 on both sides.

x=2

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Please answer the question to the best of your ability :)
Alex73 [517]

Answer:

C

Step-by-step explanation:

factorizing 24:

factors of 24 : 1, 2, 3, 4, 6, 8, 12

looking at your answer choices, we can see that 5 and 7 are not factors of 24, so we can immediately eliminate a and b.

we also see that answer c does indeed contain factors of 24 and they both add to 10. So c is the answer.

8 0
3 years ago
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Use the function s=8r+14 to find the value of s when r=3.
Phantasy [73]

Answer: s= 38


Step-by-step explanation:

S=8r+14 or S=8(3)+14

8 times 3 = 24 +14 = 38


4 0
3 years ago
Read 2 more answers
The curved surface area of cylinder is 108πcentimeter square and radius 3cm. find the height of cylinder.
bazaltina [42]

Answer:

Height= 18cm

Step-by-step explanation:

Curved surface area = 2πrh

108π = 2 * π * 3 * h

108π = 6πh

h= 108π ÷ 6π

h= 18cm

4 0
3 years ago
30 pointsssssssssssssssssssssssssssssssss
ankoles [38]
4^3 becuase 9/3=3 is correct
3 0
3 years ago
Given the following null and alternative hypotheses H0: μ1 ≥ μ2 HA: μ1 < μ2 Together with the following sample information (s
zvonat [6]

Answer:

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1

t=-1.329

p_v =P(t_{30}

With the p value obtained and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the mena of the group 1 is significantly lower than the mean for the group 2.  

Step-by-step explanation:

When we have two independnet samples from two normal distributions with equal variances we are assuming that

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

This last one is an unbiased estimator of the common variance \simga^2

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2

Our notation on this case :

n_1 =14 represent the sample size for group 1

n_2 =18 represent the sample size for group 2

\bar X_1 =565 represent the sample mean for the group 1

\bar X_2 =578 represent the sample mean for the group 2

s_1=28.9 represent the sample standard deviation for group 1

s_2=26.3 represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

\S^2_p =\frac{(14-1)(28.9)^2 +(18 -1)(26.3)^2}{14 +18 -2}=753.882

And the deviation would be just the square root of the variance:

S_p=27.457

And now we can calculate the statistic:

t=\frac{(565 -578)-(0)}{27.457\sqrt{\frac{1}{14}}+\frac{1}{18}}=-1.329

Now we can calculate the degrees of freedom given by:

df=14+18-2=30

And now we can calculate the p value using the altenative hypothesis:

p_v =P(t_{30}

So with the p value obtained and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the mena of the group 1 is significantly lower than the mean for the group 2.  

7 0
3 years ago
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