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Mrrafil [7]
3 years ago
9

Solve the equation 3(x+1 )-2=x+5

Mathematics
2 answers:
eimsori [14]3 years ago
8 0
The answer to the equation is x=2
Here’s how:

Paraphin [41]3 years ago
4 0

Answer:

x=2

Step-by-step explanation:

first, let's distribute.

3(x+1)-2=x+5

3x+3-2=x+5

then, let's combine like terms.

3x+1=x+5

now, we subtract x on both sides.

2x+1=5

subtract 1 on both sides.

2x=4

divide by 2 on both sides.

x=2

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Functions<br> F(1) if f(x)=x+3
ratelena [41]

Answer:

the ewser is 4

Step-by-step explanation:

sence x=1 1+3 =4

5 0
3 years ago
Can someone help me with this problem pls
Talja [164]
A. Slope = 2
b. Slope = 2/3 or 0.66

(Slope = change in y / change in x)
8 0
3 years ago
Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

There are 3 different possible outcomes for X.

- Godfrey pays 5p to enter the game and gets two sixes and wins 20p.

Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

= 1 - 0.0278 - 0.278 = 0.6942

Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
3 years ago
Read 2 more answers
What is the value of x in the equation x - 2/3 + 1/6 = 5/6?<br><br> 1) 4<br> 2) 6<br> 3) 8<br> 4) 11
Licemer1 [7]

Answer:

\large\boxed{x=\dfrac{4}{3}=1\dfrac{1}{3}}

Step-by-step explanation:

x-\dfrac{2}{3}+\dfrac{1}{6}=\dfrac{5}{6}\qquad\text{multiply both sides by 6}\\\\6x-6\!\!\!\!\diagup^2\cdot\left(\dfrac{2}{3\!\!\!\!\diagup_1}\right)+6\!\!\!\!\diagup^1\cdot\left(\dfrac{1}{6\!\!\!\!\diagup_1}\right)=6\!\!\!\!\diagup^1\cdot\left(\dfrac{5}{6\!\!\!\!\diagup_1}\right)\\\\6x-(2)(2)+1=5\\\\6x-4+1=5\\\\6x-3=5\qquad\text{add 3 to both sides}\\\\6x=8\qquad\text{divide both sides by 6}\\\\x=\dfrac{8}{6}\\\\x=\dfrac{8:2}{6:2}\\\\x=\dfrac{4}{3}

3 0
3 years ago
Read 2 more answers
Cathrine has £7000 to invest.
Anvisha [2.4K]
Since this is a compound interest problem, you have to take note that the amount Catherine will get per year is not the same. It will increase per year since it is compounded. So first, we get the amount after one year. This will be 7000 x 0.04 which is 280 plus 7280. In the second year, she will get 7571 (7280 x 0.04 + 7280). In the third year, she will get 7874 (7571 x 0.04 + 7571). In the fourth year, she will get 8189 (7874 x 0.04 + 7874). And finally in the fifth year, she will get 8517 (8189 x 0.04 +8189). So after five years, she has 8517
4 0
3 years ago
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