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3 years ago

Solve the equation 3(x+1 )-2=x+5

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

The answer to the equation is x=2
Here’s how:

Paraphin [41]3 years ago

4 0

Answer:

x=2

Step-by-step explanation:

first, let's distribute.

3(x+1)-2=x+5

3x+3-2=x+5

then, let's combine like terms.

3x+1=x+5

now, we subtract x on both sides.

2x+1=5

subtract 1 on both sides.

2x=4

divide by 2 on both sides.

x=2

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The amount of time it takes Ariana to do a math problem is continuous and uniformly distributed between 38 seconds and 79 second

solniwko [45]

Answer:

29.27% probability that it takes Ariana between 58 and 70 seconds to do a math problem

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d, d being greater than c, is given by the following formula:

$P(c \leq X \leq d) = \frac{d-c}{b-a}$

Uniformly distributed between 38 seconds and 79 seconds.

This means that $a = 38, b = 79$

What is the probability that it takes Ariana between 58 and 70 seconds to do a math problem

$c = 58, d = 70$

$P(58 \leq X \leq 70) = \frac{70 - 58}{79 - 38} = 0.2927$

29.27% probability that it takes Ariana between 58 and 70 seconds to do a math problem

4 0

3 years ago

Some number added to seventeen

Oksanka [162]

Answer:

x+17

Step-by-step explanation:

x + 17 is the answer

5 0

4 years ago

484,343 rounded to the nearest thousand

Semmy [17]

Answer:

484,000

Step-by-step explanation:

The hundreds place is less than 5 so you round down.

3 0

3 years ago

Read 2 more answers

For any number n>1, is

Simora [160]

The right answer is A ! :)

7 0

3 years ago

Triangle $ABC$ has a right angle at $B$. Legs $\overline{AB}$ and $\overline{CB}$ are extended past point $B$ to points $D$ and

Lisa [10]

Answer:

Given :

ABC is a right triangle in which ∠ABC = 90°,

Also, Legs AB and CB are extended past point B to points D and E,

Such that,

$\angle EAC = \angle ACD = 90^{\circ}$

To prove :

$EB\times BD=AB\times BC$

Proof :

In triangles AEC and EBA,

∠EAC= ∠ABE ( right angles )

∠CEA = ∠AEB ( common angles )

By AA similarity postulate,

$\triangle AEC \sim \triangle EBA$ ,

Similarly,

$\triangle AEC \sim \triangle ABC$

$\implies\triangle EBA\sim \triangle ABC-----(1)$

Now, In triangles ADC and CBD,

∠ACD = ∠CBD ( right angles )

∠ADC= ∠BDC ( common angles )

By AA similarity postulate,

$\triangle ADC \sim \triangle CBD$ ,

Similarly,

$\triangle ADC \sim \triangle ABC$

$\implies \triangle CBD\sim \triangle ABC-----(2)$

From equations (1) and (2),

$\triangle EBA\sim \triangle CBD$

The corresponding sides of similar triangles are in same proportion,

$\frac{EB}{BC}=\frac{AB}{BD}$

$\implies EB\times BD=AB\times BC$

Hence, proved....

5 0

3 years ago