Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
Answer: 
Step-by-step explanation:
Given the angle of 55 degrees, you know that the adjacent side is "x" and the length of the hypotenuse is 20.
Therefore, you need to remember the following identity:

Then, knowing that:

You need to substitute these values into
:

Now, you can solve for "x":

Rounded to the nearest hundreth:

(12x+6x-30x-10)/(x-3)=
=(-12x-10)/(x-3)
=-12x*+36- 10x+30=
=-22x+56
Answer:
5,18,12 cms are the answer.
Step-by-step explanation:
Given is a triangle ABC. Point D is the centroid.
E,F and G are midpoints of CB, BA and AC respectively.
AE, BF and CG are medians of the triangle.
We know that centroid divides the median in the ratio 2:1
Using this we find that AD:DE = 2:1
Or AD+DE:DE = (2+1):1
AE:DE =3:1
15:DE = 3:1 . Hence DE =5 cm.
On the similar grounds we find that DF = 1/3 BF = 9
Hence BD = DF-BF = 27-9 =18 cm
and also
CG = 3/2 times CD = 12 cm.
Answer -> (12) I'm very late haha but hopes this helps!