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aev [14]
3 years ago
5

Two questions please help?

Mathematics
2 answers:
eduard3 years ago
6 0

Answer:

The area of triangle PQR is

A=21.5\ cm^{2}

Step-by-step explanation:

we know that

The area of a triangle is equal to

A=\frac{1}{2}bh

see the attached figure to better understand the problem

we have

b=14\ cm

h=PS\ cm

Find the length side of segment PS

In the right triangle PSR

sin(20\°)=\frac{PS}{PR}

Solve for PS

PS=PRsin(20\°)

we have

PR=9\ cm

substitute

PS=(9)sin(20\°)

Find the area of the triangle PQR

A=\frac{1}{2}(14)((9)sin(20\°))

A=21.5\ cm^{2}

FromTheMoon [43]3 years ago
3 0
21.5, just took the test!!!!
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