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umka21 [38]
3 years ago
10

Consider the continuous random variable x, which has a uniform distribution over the interval from 20 to 28. refer to exhibit 6-

1. the probability that x will take on a value between 21 and 25 is
Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0
(25 -21)/(28 -20) = 4/8 = 1/2

Your probability is 1/2.
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SOMEONE PLZ HELP ME WITH 10 and 8!!!!!
Allisa [31]

Answer:

10.23.75^{o}

8. 34.76^{o}

Step-by-step explanation:

10. each step is 36, so i added it twice to get 72.

     then add 16 twice = 32

      this gives us two sides to our triangle.

      We can now use tan since we know opp and adj

      tan 32/72 = .44

      arctan = 23.75

8. since we again know the opposite and adjacent sides to the angle e are trying to find we can use tan again.

  tan 12.5/18 = .694

  arctan= 34.76

5 0
3 years ago
Which one express a ratio between 3/4, 3:4, 3 of 4 , 3 to 4
Alex777 [14]

Answer:

3/4, 3:4, 3 to 4

Step-by-step explanation:

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2 years ago
Please answer this question and i will mark you brainliest.
juin [17]

Answer:

4 altogether

0,1 + 1, 1 = 1 RA

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Step-by-step explanation:

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3 years ago
What is the x-coordinate of the solution of the system?<br> x+y+3<br> 4x-y=-38
steposvetlana [31]

<em>Note: I am assuming the first equation is:</em>

<em>x+y = 3</em>

Answer:

The solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

Step-by-step explanation:

Given the system of equations

\begin{bmatrix}x+y=34\\ x-y=-38\end{bmatrix}

subtracting the equations

x-y=-38

-

\underline{x+y=34}

-2y=-72

solve -2y for y

-2y=-72

Divide both sides by -2

\frac{-2y}{-2}=\frac{-72}{-2}

y=36

For x+y=34 plug in y = 36

x+36=34

Subtract 36 from both sides

x+36-36=34-36

Simplify

x=-2

Thus, the solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

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3 years ago
Calcula x para que sean ciertas las igualdades siguientes:
ZanzabumX [31]
A. 81
b. no entiendo la pregunta
c. 32
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