Let Angle B be an acute angle in a right triangle. Approximate the measure of Angle B to

Mathematics

1 answer:

anastassius [24]3 years ago

8 0

Answer:

75.3°

Step-by-step explanation:

-To find the measure of angle B we find the cos inverse of B.

-Given cos B=0.2536, it's cos inverse is calculated as:

$\angle B=Cos ^{-1} (Cos \ B)\\\\=Cos^{-1}(0.2536)\\\\=75.3\textdegree$

Hence, the approximate measure of B is 75.3°

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Dr. Cyril conducts a simple random sample of 500 men who became fathers for the first time in the past year. He finds that 23% o

svlad2 [7]

Answer:

The another term for the 4% value is : Margin of error

Step-by-step explanation:

Dr. Cyril conducts a simple random sample of 500 men.

He finds that 23% of them report being unsure of their ability to be good fathers, plus or minus 4%.

Now, the another term for the 4% value is : Margin of error

Means the estimate of father being unsure about his ability would be between 19% and 27%.

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3 years ago

The College Board originally scaled SAT scores so that the scores for each section were approximately normally distributed with

likoan [24]

Answer:

Percentage of students who scored greater than 700 = 97.72%

Step-by-step explanation:

We are given that the College Board originally scaled SAT scores so that the scores for each section were approximately normally distributed with a mean of 500 and a standard deviation of 100.

Let X = percentage of students who scored greater than 700.

Since, X ~ N( $\mu, \sigma^{2}$ )

The z probability is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1) where, $\mu$ = 500 and $\sigma$ = 100

So, P(percentage of students who scored greater than 700) = P(X > 700)

P(X > 700) = P( $\frac{X-\mu}{\sigma}$ < $\frac{700-500}{100}$ ) = P(Z < 2) = 0.97725 or 97.72% Therefore, percentage of students who scored greater than 700 is 97.72%.