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mihalych1998 [28]
3 years ago
10

Sighting from a helicopter:A helicopter hovered at an altitude that is 1000 feet above a mountain peak of altitude 5210 feet A s

econd taller peak is viewed from both the mountaintop and helicopter. From the helicopter, the angle of depression is 43 and from the mountaintop, the angle of elevation is 18 how far apart are the mountain peak? What is the altitude of the taller peak?

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
5 0
We can conclude that the the two peaks are 816.11 feet apart, and the altitude of the taller peak is 5475.17 feet.

Please check the detailed explanation in the images attached, and let me know what you think. :) 

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The other integer is -25

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3 years ago
Trevor is analyzing a circle, y2 + x2 = 100, and a linear function g(x). Will they intersect?
lakkis [162]
Given a circle described by the equation:
y^2+x^2=100
and a function g(x) given by the table
\begin{center}
\begin{tabular}{ |c |c |c }
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1 & -18   
\end{tabular}
\end{center}

The function g(x) describes a straight line with the equation:
\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}  \\  \\  \frac{y-(-22)}{x-(-1)} = \frac{-20-(-22)}{0-(-1)}  \\  \\ \frac{y+22}{x+1} = \frac{-20+22}{0+1} = \frac{2}{1}  \\  \\ y+22=2(x+1)=2x+2 \\  \\ y=2x-20

To check if the circle and the line intersects, we substitute the equation of the line into the equation of the circle to see if we have a real solution.
i.e.
y^2+x^2=100 \\  \\ (2x-20)^2+x^2=100 \\  \\ 4x^2-80x+400+x^2=100 \\  \\ 5x^2-80x+300=0 \\  \\ x^2-16x+60=0 \\  \\ (x-6)(x-10)=0 \\  \\ x-6=0 \ or \ x-10=0 \\  \\ x=6 \ or \ x=10

When x = 6, y = 2(6) - 20 = 12 - 20 = -8 and when x = 10, y = 2(10) - 20 = 20 - 20 = 0

Therefore, the circle and the line intersect at the points (6, -8) and (10, 0).
8 0
4 years ago
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6 0
4 years ago
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baherus [9]

Answer:

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Step-by-step explanation:

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Since, we are given the sample standard deviation instead of the population standard deviation, we will use t-test to find the confidence interval.

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The formula to calculate the confidence interval is:

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I believe it’s 80 hope it helps
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