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Zinaida [17]
3 years ago
7

Which expression is equivalent to...? Screenshots attached, please help.

Mathematics
1 answer:
BaLLatris [955]3 years ago
3 0

For this case we must simplify the following expression:

\sqrt [3] {64 * a ^ 6 * b ^ 7 * c ^ 9}

We rewrite:

64 = 4 ^ 3\\a ^ 6 = (a ^ 2) ^ 3\\b ^ 6 * b = ((b ^ 2) ^ 3 * b)\\c ^ 9 = (c ^ 3) ^ 3

So:

\sqrt [3] {4 ^ 3 * (a ^ 2) ^ 3 * (b ^ 2) ^ 3 * b * (c ^ 3) ^ 3} =\\\sqrt [3] {4 * a ^ 2 * b ^ 2 * c ^ 3) ^ 3 * b} =

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

So:

4a ^ 2b ^ 2 c ^ 3 \sqrt [3] {b}

Answer:

Option B

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Jamie is saving to buy a video game system. He has saved $16, which is 5% of the total cost. What is the cost of the video game
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$320 5 times 20 is 100 so you have to times 16 by 20 to get the total 100% of the video game system
4 0
3 years ago
If an angle is acute, then the measure of its complement must be greater than the measure of its
salantis [7]

Answer: acute angles are higher that 0° and smaller than 90°

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5 0
2 years ago
What two numbers multiply to -20 then add to -8?
VARVARA [1.3K]

Answer:

-10 and 2

Step-by-step explanation:

1.  Think about what numbers multiply to -20:  -10 and 2, 10 and -2, -20 and 1, 20 and -1, 4 and -5, -4 and 5

2.  Then, think about which of the above adds to -8.  This leaves you with -10 and 2

7 0
2 years ago
Read 2 more answers
If it is true that z2 - 6 = 19, then z2 + 6 = ?
qwelly [4]
The answer is probably the opposite which in this case would be -19 ?
5 0
3 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
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