What are 3 angles that are congruent to <4
1 answer:
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Answer: Option c. D: all real numbers R: (y ≥ 8.75)
Solution:
y=x^2+x+9
Domain: all real numbers = ( - Infinite, Infinite)
y=ax^2+bx+c
a=1 > 0, the parabola opens upward: Range: y ≥k
b=1
c=9
Vertex: V=(h,k)
h=-b/(2a)
h=-1/(2(1))
h=-1/2
h=-0.5
k=y=h^2+h+9
k=(-0.5)^2+(-0.5)+9
k=0.25-0.5+9
k=8.75
Range: y≥k
Range: y≥8.75
The solution to this system is (x, y) = (8, -22).
The y-values get closer together by 2 units for each 2-unit increase in x. The difference at x=2 is 6, so we expect the difference in y-values to be zero when we increase x by 6 (from 2 to 8).
You can extend each table after the same pattern.
In table 1, x-values increase by 2 and y-values decrease by 8.
In table 2, x-values increase by 2 and y-values decrease by 6.
The attachment shows the tables extended to x=10. We note that the y-values are the same (-22) for x=8 (as we predicted above). That means the solution is ...
... (x, y) = (8, -22)
