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WITCHER [35]
4 years ago
9

PLEASE! Need help on number 28. Explanation also. Thanks

Mathematics
1 answer:
lys-0071 [83]4 years ago
4 0
If the bleachers seat only 60 people then you should subtract 60 from 450 so that you know how many people are left to fill in the 26 rows. 450-60 is 390
There are 390 people left and 26 rows 
Divide 390 by 26 so that you will find out how many people you can seat per row. 
390/26 is 15 
Your answer is 15 people per row
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Jacob runs 5 miles in 1 1/2 hours . Robert runs 3 miles in 45 minutes or 3/4 hour. Who runs faster
IgorLugansk [536]

Answer:

Robert

Step-by-step explanation:

If Robert runs 3 miles in 45 minutes, by the end of 90minutes, Robert would have covered 6miles, while Jacob covered 5miles in 90 minutes, therefore, Robert ran faster than Jacob.

5 0
3 years ago
Can anyone explain how this problem is done ?
Svetach [21]

B

Step-by-step explanation:

6 0
3 years ago
Help with these two
kupik [55]
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5 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
Which graph is NOT a function?
Solnce55 [7]

Step-by-step explanation:

Use the vertical line test to determine whether or not a graph represents a function. If a vertical line is moved across the graph and, at any time, touches the graph at only one point, then the graph is a function. If the vertical line touches the graph at more than one point, then the graph is not a function.

my only advice

5 0
3 years ago
Read 2 more answers
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