(a+b+c)/2. this is your answer. if it had the numbers i would solve it fully, but it only has variables.
This is a common factor problem.
Pencils come in a pack of 12
Erasers come in a pack of 10
First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3
So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers
I hope this helps. Let me know if you have any questions!!
We know that 7/10 of the cookies are chocolate chip, so that means there are 3/10 of the cookies left.
We now want to find what 3/4 of 3/10 is.
We can do this by multiplying both fractions
3/4x3/10 (we just multiply across) to get 9/40.
We cannot simplify this answer, so our final answer is 9/40 of the cookies are sugar cookies.
Answer:


Step-by-step explanation:
Note that the entire segment RT is the combined lengths of RS and ST. So:

We know that RT is 108, RS is (9y+5), and ST is (3y+7). Substitute:

On the right, combine like terms:

Add:

Subtract 12 from both sides. The right cancels:

Divide both sides by 12:

So, the value of y is 8.
To find RS and ST, substitute 8 for y. So:

Substitute 8 for y:

Multiply:

Add:

Do the same for ST:

Substitute 8 for y:

Multiply:

Add:

Ignore the scribbles
Search up Elimination and substitution