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dusya [7]
3 years ago
13

If a circle has the dimensions​ given, determine its circumference.

Mathematics
2 answers:
Shtirlitz [24]3 years ago
8 0

Answer:B

Step-by-step explanation:

sergij07 [2.7K]3 years ago
6 0

The answer is B

Hope this helps;)

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Add and simplify (-4+n-2n^2)+(2-5n-6n^2)
Lelechka [254]
Your answer is - 2 - 4n - 8n² after you combine like terms. 
7 0
3 years ago
I need help you solve this by using elimination and substitution thank you
AnnZ [28]

Answer: Just use MathPapa.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the factored form of 2x^3+ 4x^2- x?
ryzh [129]

Answer:

x (2 x^2 + 4 x - 1)

Step-by-step explanation:

Factor the following:

2 x^3 + 4 x^2 - x

Factor x out of 2 x^3 + 4 x^2 - x:

Answer:  x (2 x^2 + 4 x - 1)

7 0
4 years ago
Brian invests £4900 into his bank account.
True [87]

Answer:

  • £5200.68

Step-by-step explanation:

<u>Given:</u>

  • Investment P = £4900
  • Interest rate r = 1.5% or r = 0.015
  • Time t = 4 years
  • Number of compounds per year n = 1

<u>Find the future amount:</u>

  • F = P*(1+r/n)^{nt}\\
  • F = 4900*(1+0.015/1)^{1*4}=4900*1.015^4 = 5200.68
6 0
2 years ago
Read 2 more answers
PLEASE HELP ME ASAP!!!! My entire grade depends on these questions and I need to show the work that go me there
Marizza181 [45]

Answer:

Answers are in bold

Step-by-step explanation:

<u></u>

<u>Part 1A</u>

Use the Zero Product Property to find the x-intercepts:

0=-(x+4)(x-1)

0=(x+4)(x-1)

0=(x+4)

-4=x

x=-4

0=(x-1)

1=x

x=1

So the x-intercepts are x=-4 and x=1 which is also (-4,0) and (1,0)

For the y-intercepts, plug in x=0:

f(x)=-(0+4)(0-1)

f(x)=(-4)(-1)

f(x)=4

So the y-intercept is y=4 which is also (0,4)

<u>Part 1B</u>

In general, the axis of symmetry is equal to x=h in the equation y=(x-h)^2+k

For a parabola, the axis of symmetry is equal to x=-b/2a, so we expand the given equation and then plug in the values of "a" and "b" to get the axis of symmetry:

f(x)=-(x+4)(x-1)

f(x)=-(x^2+3x-4)

f(x)=-x^2-3x+4

So now we know a=-1 and b=-3, therefore we can plug them in:

x=-b/2a

x=-(-3)/2(-1)

x=3/-2

x=-3/2

x=-1.5

So the equation of the axis of symmetry is x=-1.5

<u>Part 1C</u>

We'll use the equation x=-b/2a to get the x-coordinate for the vertex (which we already know is x=-1.5), then plug in that value of x in the original equation to get the y-coordinate for the vertex:

f(x)=-(-1.5+4)(-1.5+1)

f(x)=-(2.5)(-0.5)

f(x)=-(-1.25)

f(x)=1.25 <-- y-coordinate

So the coordinates of the vertex are (-1.5,1.25)

<u>Part 1D</u>

See the image below

I'll let someone else do the last 4 questions as I am unable to answer them.

<u></u>

8 0
3 years ago
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