1. Q
2. QS
3. RST
4. Q
(I'm not sure that I am right.)
Answer:
a. 15 meters.
b. 20 meters.
Step-by-step explanation:
a. The height of the ball at 3 seconds. 20 * 3 - 5 * (3)^2 = 60 - 5 * 9 = 60 - 45 = 15.
The ball will be 15 meters high.
b. The maximum height reached by the ball.
To get that, we need to find the vertex of the parabola. We do so by doing -b/2a to find the x-coordinate of the vertex.
In this case, a = -5 and b = 20.
-20 / 2(-5) = -20 / -10 = 20 / 10 = 2.
Then, we find the y-coordinate by putting 2 where it says "t".
h(2) = 20(2) - 5(2)^2 = (40) - 5(4) = 40 - 20 = 20 meters.
Hope this helps!
The results are biased.
When you go to a particular sporting event and ask someone their favorite sport, they are more likely to respond the sport that they're watching at that moment. This creates bias.
You need to solve this for h(t)=0
<span>-16t^2-30t+124=0
This has two solutions, one is negative that does not make sense as time cannot be negative.
The positive solution is t=2
So the interval where it is in the air is [0;2)
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