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UkoKoshka [18]
2 years ago
11

How do I solve this ?

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
6 0

Answer:

See attachment :D

Step-by-step explanation:

y = 2/3x + 2

This is in slope-intercept form, y = mx+b. m is the slope, 2/3, and b is the y- intercept, 2. So you know the line intersects with the y-axis at (0,2). The slope is 2/3. So you can move up two points, then over three. Because it's a positive slope, you move right. This leaves you at point (0,3). Connect a line between these two points.

The line intersects with points (-3,0) and (0,2).

Hope this is helpful ^^ Good luck with your test :D

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Is -32 greater than or less than -97?<br><br> need answer fast pls
ikadub [295]

Answer: greater than

Step-by-step explanation:

This is because the "higher" the negative number, the less valuable. Imagine this, would it be better if you owed 32 dollars or 97 dollars? 32 because you don'y owe as much. The farther away from 0, the smaller the number is. -97 is farther than -32 from 0, so -97 is less than.

8 0
2 years ago
Here we will study the function f (x) = e ^ x sin (x), where x ∈ [0, 2π]. a) Determine where the function is decreasing and incr
Semmy [17]

fff

f(x) = e^x sin (x)

To find increasing and decreasing intervals we take derivative

f'(x) = e^xsin(x)+e^x(cosx)= e^x(sinx+cosx)

Now we set the derivative =0  and solve for x

e^x(sinx+cosx)=0

sinx + cosx =0

divide whole equation by cos x

\frac{sinx}{cosx} + \frac{cosx}{cosx} =0

tanx +1 =0

tanx = 1

x=\frac{3\pi }{4} and  x=\frac{7\pi}{4}

Now we pick a number between 0 to  \frac{3\pi }{4}

Lets pick  \frac{\pi }{2}

Plug it into the derivative

f'(x) =e^{\frac{\pi }{2}}(sin(\frac{\pi}{2})+cos(\frac{\pi }{2}))

= 4.810 is positive

So the graph of f(x) is increasing on the interval [0, x=\frac{3\pi }{4})

Now we pick a number between   \frac{7\pi}{4} to 2pi

Lets pick  \frac{11\pi}{6}

Plug it into the derivative

f'(x) =e^{\frac{11\pi}{6}}(sin(\frac{11\pi}{6})+cos(\frac{11\pi }{6}))

= 116 is positive

So the graph of f(x) is increasing on the interval (\frac{7\pi }{4}, 2\pi)

Increasing interval is (0,\frac{3\pi }{4}) U (\frac{7\pi }{4}, 2\pi)

Decreasing interval is (\frac{3\pi}{4}, \frac{7\pi}{4})

(b)

The graph of f(x) increases and reaches a local maximum at x=\frac{3\pi}{4}

The graph of f(x) decreases and reaches a local minimum at x=\frac{7\pi}{4}

(c)

f(0) = 0

f(2\pi)=0

f(\frac{3\pi }{4})=7.46

f(\frac{7\pi}{4})=-172.64

Here global maximum at x=\frac{3\pi}{4}

Here global minimum at x=\frac{7\pi}{4}


3 0
3 years ago
Read 2 more answers
A contest is being held at a school fair for seventh-grade
pshichka [43]

Answer:

3/7

Step-by-step explanation:

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6 0
2 years ago
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In order to fairly set flat rates for auto mechanics, a shop foreman needs to estimate the average time it takes to replace a fu
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Answer:

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Step-by-step explanation:

yw

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Please help me on this problem.​
S_A_V [24]

Answer:

A) 0.6 B) 0.4 C) 0.8

Step-by-step explanation:

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A) 3/5=0.6

B) 2/5=0.4

C) 4/5=0.8

6 0
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