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Salsk061 [2.6K]
4 years ago
14

In order to solve the following system of equations by addition, which of the following could you do before adding the equations

so that one variable will be eliminated when you add them ?
3x -6y = -15
-2x + 5y = 14
A. Multiply the top equation by 2 and the bottom one by 3.
B. Multiply the top equation by -3 and the bottom one by 2.
C. Multiply the top equation by 2.
D. Multiply the bottoms equation by 6.
Mathematics
1 answer:
alexandr402 [8]4 years ago
5 0
To solve the question, the both equations should have a positive value and a negative value with same number. Then one variable can be eliminated.

To eliminate X term first, we should multiply the first equation by 2 and second one by 3.
Then,
     6X - 12Y = -30
     -6X + 15Y = 70

Or

To eliminate Y term first, we should multiply the first equation by 5 and second one by 6.
 Then,
     15X - 30Y = -75
      -12X + 30Y = 84

According to the choices given 'A' is the correct answer.

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mariarad [96]

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The correct option is;

DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC)

Step-by-step explanation:

Given that we have;

1) The side AD of the angle m∠ADE corresponds to the side AB of the angle m∠ABC

2) The side DE of the angle m∠ADE corresponds to the side BC of the angle m∠ABC

3) The side AE of the angle m∠ADE corresponds to the side AC of the angle m∠ABC

Then when we have DE = 2·(BC), AD = 2·(AB), and AE = 2·(AC), we have by sin rule;

AE/(sin(m∠ADE)) = 2·(AC)/(sin(m∠ABC)) = AE/(sin(m∠ABC))

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3 years ago
A package states that there are 60 calories in 12 crackers and 75 calories in 15 crackers. Since the relationship is proportiona
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6 0
3 years ago
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What fraction of 3 is 2 2/5
Yuki888 [10]

Answer: 2 2/5 is 4/5 of 3

Step-by-step explanation:

We can view that as what do we multiply 3 by to get 2 2/5 and call that value x

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x = (2 2/5)/3

Let's turn 2 2/5 into an improper fraction... 2 2/5 = 12/5

So we have

x = (12/5)/3 = (12/5)(1/3) = 4/5

Thus 2 2/5 is 4/5 of 3

Verify:  3(4/5) = 12/5 = 2 2/5

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3 years ago
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