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xeze [42]
3 years ago
13

Write expression without using exponents. X^2

Mathematics
1 answer:
wariber [46]3 years ago
6 0

Answer:

x(x) or x*x

Step-by-step explanation:

To write this in the expanded form you just multiply the base(x) by itself

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How much is $800 bonus for a year add to your hourly rate​
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eine Menge Geld

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The two basic types of methods used to trace and assign product costs are
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c.) product costing and materials inventory costing.

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Product costing methods are used to assign a cost to a manufactured product. The main costing methods available are process costing, job costing, direct costing, and throughput costing. Each of these methods applies to different production and decision environments.

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The ratio of the girls to the total number of students in class is 47 how many students are girls in the class has 21 students a
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4 years ago
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he time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the a
Eva8 [605]

Answer:

The answer is below

Step-by-step explanation:

The time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the answers to 3 decimal places.

(a) What is the probability that more than three aircraft arrive within an hour?

(b) If 30 separate one-hour intervals are chosen, what Is the probability that no interval contains more than three arrivals?

(c) Determine the length of an interval of time (in hours) such that the probability that no arrivals occur during the interval is 0.1.

Solution:

a) A poisson distribution is given by the formula:

P(X=x)=\frac{e^{-\lambda }\lambda^x}{x!}

λ = 1 hour

Therefore:

P(X > 3) = 1 - P(X < 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(x = 3)]

P(X=0)=\frac{e^{-1}*1^0}{0!}=0.3679

P(X=1)=\frac{e^{-1}*1^1}{1!}=0.3679

P(X=2)=\frac{e^{-1}*1^2}{2!}=0.1839

P(X=3)=\frac{e^{-1}*1^3}{3!}=0.0613

P(X > 3) = 1 - [0.3679+0.3679 + 0.1839 + 0.0613] = 0.019

b) Assuming 30 1 hour intervals, hence:

P(X \leq 3)^{30}=[1-P(X\geq 30)]^{30}=(1-0.019)^{30}=0.5624

c) mean = 1 hour

mean = 1 / λ

1 = 1 / λ

λ = 1

The cumulative distribution function of a continuous variable is:

F(x)=1-e^{-\lambda x}

0.1=1-F(x)\\\\0.1=1-(1-e^{- x})\\\\0.1=e^{- x}\\\\-x=ln(0.1)\\\\-x = -2.3\\\\x=2.3\ hours

4 0
3 years ago
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