Ask question

Ask question

All categories

GarryVolchara [31]

2 years ago

14

On April 3rd nears flag company borrowed 10,000 dollars to pay for start up costs the loan had a simple interest rate of 6.25 pe

rcent for 230 days the company made partial payments of 5000 dollars on May 28th and 3500 on October 12 how much will the company owe on the date of maturity

1 answer:

Alchen [17]2 years ago

8 0

Answer:

At the end of the maturity, company owes $1893.75.

Step-by-step explanation:

The principal amount borrowed = $10,000

Rate of interest = 6.25%

Time (in year) = 230 days =(230/365) year

Simple Interest = $\frac{P\times R \times T}{100}$

So, here SI = $\frac{10,000 \times 6.25 \times 230}{ 365 \times 100}$

= $393.75

So, simple interest after 230 days = $393.75

Now, the amount to be paid after the end of 230 days = Principal + interest

A = $10,000 + $393.75 = $ 10,393.75

The total partial payment made within year = $3500 + $5000 = $8500

So, the remaining payment = Total amount - Total partial payments

= $ 10,393.75 - $8,500 = $1893.75

Hence, at the end of the maturity, company owes $1893.75.

You might be interested in

Choose the right answer.

kramer

Answer:

In this section, we discuss box-and-whisker plots and the five key values. The key values are called a five-number summary, which consists of the minimum, first quartile, the set is put into increasing order, divides the data into two equal parts. First, we put the values in the data set into increasing order: 3, 5, 7, 8, 12, 13, the middle score for a set of data that has been arranged in order from least to greatest. A box-and-whisker plot shows the distribution of a set of data along with... Quartiles are values that divide a set of data into four equal parts. The second Quartile ( designated Q2) also called the median or the 50th percentile (cuts data set in half ).

Step-by-step explanation:

5 0

2 years ago

HELP PLEASE!!! 10 PTS!!

allsm [11]

Answer:

m∠DEC = 78°

Step-by-step explanation:

Given information: AC = AD, AB⊥BD, m∠DAC = 44° and CE bisects ∠ACD.

If two sides of a triangles are congruent then the opposite angles of congruent sides are congruent.

AC = AD (Given)

$\angle ADC\cong \angle ACD$

$m\angle ADC=m\angle ACD$

According to the angle sum property, the sum of interior angles of a triangle is 180°.

$m\angle ADC+m\angle ACD+m\angle DAC=180$

$m\angle ACD+m\angle ACD+44=180$

$2m\angle ACD=180-44$

$2m\angle ACD=136$

Divide both sides by 2.

$m\angle ACD=68$

CE bisects ∠ACD.

$m\angle ACE=m\angle DCE=\dfrac{\angle ACD}{2}$

$m\angle ACE=m\angle DCE=\dfrac{68}{2}$

$m\angle ACE=m\angle DCE=34$

Use angle sum property in triangle CDE,

$m\angle CDE+m\angle DCE+m\angle DEC=180$

$68+34+m\angle DEC=180$

$68+34+m\angle DEC=180$

$102+m\angle DEC=180$

Subtract 102 from both sides.

$m\angle DEC=180-102$

$m\angle DEC=78$

Therefore, the measure of angle DEC is 78°.

6 0

2 years ago

A explanation also would be super helpful and very appreciated!

xxTIMURxx [149]

Answer:

26%

Step-by-step explanation:

345. 24 - 274 = 71.24

71.24 / 274 =0.26

0.26 * 100 = 26

8 0

2 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

4 0

1 year ago

Dawson is covering a large cylinder with brown paper. He'll need to find the volume of the cylinder in order to determine how mu

Arlecino [84]

It is to true!!!!!!!!!!!!!!!!!!!!!!!!

3 0

2 years ago